The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is 4x²
Answer:
f(x) = + cosx or - cosx
Step-by-step explanation:
(2+tan^2x/sec^2x) -1 =(f(x))^2
=(( 1 + sec^2x)/sec^2x) -1
= 1 / sec^2x + 1 - 1
= 1 / sec^2x
= cos^2x
(f(x))^2 = cos^2x
f(x) = + cosx or - cosx
<h3>17 heavy equipment operators and 14 general labourers were employed</h3>
<em><u>Solution:</u></em>
Let x = number of heavy equipment operators employed
Then,
31 - x = number of laborers employed
From given,
Pay of heavy equipment operators = $ 138 per day
Pay of general labours = $ 93 per day
Payroll was $3648
Therefore,
number of heavy equipment operators x Pay of heavy equipment operators + number of laborers employed x Pay of general labours = 3648
138x + 93(31 - x) = 3648
138x + 2883 - 93x = 3648
45x = 3648 - 2883
45x = 765
x = 17
Thus,
31 - x = 31 - 17 = 14
Therefore, 17 heavy equipment operators and 14 general labourers were employed
Answer:
She paid back $192 in interest
Step-by-step explanation:
A = P(1+r)^n
P = $1,200
r = 10.5% = 0.105
n = 18 months = 18/12 = 1.5 years
A = 1,200(1+0.105)^1.5 = 1,200(1.105)^1.5 = 1,200×1.16 = 1,392
Amount = $1,392
Principal = $1,200
Interest = amount - principal = $1,392 - $1,200 = $192
Given two points, say points
A and
B, we can use the slope formula to find the slop of the line:
If
A has coordinates of
(w,c) and
B has coordinates of
(y,z), we can find the slope.
![\frac{z-c[tex]y-w= \frac{z-x}{y-w} (x-c)](https://tex.z-dn.net/?f=%20%5Cfrac%7Bz-c%5Btex%5Dy-w%3D%20%5Cfrac%7Bz-x%7D%7By-w%7D%20%28x-c%29)
}{y-w} [/tex]
Now we can say that we can use the point slope form formula:
Now we can substitute
m for the slope, and use any points to plug in
and
.
Hope this helps! :^)
