Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)
Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
14 - pHi - log 2 = 14 - pH
In terms of pHi,
pH = pHi + log 2
Answer:
0.254 M
Explanation:
If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.
Also, 750 mL = 0.750 L.
molarity = (moles of solute)/(liters of solution)
molarity = 0.190768/0.750 = <u>0.254</u><u> </u><u>M</u>
I think is 4 but Iam not sure
They would be found in shallow rivers because it would be easiest for them to find there food in a shallow river. and i go fishing so i know
