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RUDIKE [14]
2 years ago
12

Calculate the molarity of 65.3 grams of sugar(342.3 g/mol), c12h22011 in 750 ml of solution.

Chemistry
1 answer:
k0ka [10]2 years ago
8 0

Answer:

0.254 M

Explanation:

If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.

Also, 750 mL = 0.750 L.

molarity = (moles of solute)/(liters of solution)

molarity = 0.190768/0.750 = <u>0.254</u><u> </u><u>M</u>

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What mass of carbon dioxide is produced upon complete combustion
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3 years ago
MY NOTES ASK YOUR TEACHER Consider a different titrant for this exercise. Suppose Ca(OH)2 were used as the titrant, instead of N
Alekssandra [29.7K]

Answer:

Two moles of HC2H3O2 react with one mole of Ca(OH)2 to produce one mole of calcium acetate and two moles of water.

Explanation:

HC2H3O2 is Acetic acid that can also be represented as (CH3COOH).

when Ca(OH)2 reacts with Acetic acid the product formed will be Calcium acetate and water

Chemically the reaction can be represented as

2CH 3 COOH + Ca(OH) 2    →      Ca(CH 3 COO) 2   +    2H 2 O

Two moles of CH3COOH react with one mole of Ca(OH)2 to produce one mole of Ca(CH3COO)2 and two moles of H2O.

7 0
3 years ago
. how many lone pairs of electrons are present in the lewis structure of calcium sulfide?
miv72 [106K]
Answer:
            <u>Four</u>

Explanation:
                     Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.
Ca²⁺ is formed as,

                                   Ca    →    Ca²⁺  +  2 e⁻

These two electrons are accepte by Sulfur as,

                                     S  +  2 e⁻    →    S²⁻

So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs as shown below,

7 0
3 years ago
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