Hello : let A(3,0) B(0,-5)<span>
the slope is : (YB - YA)/(XB -XA)
(-5-0)/(0-3) = 5/3
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<span> an equation, in the slope intercept form is : y - (-5) = (5/3)(x-0)
y = (5/3)x - 5</span>
1) 2x + 3y = 12 -> 3y = -2x +12 -> y = -2/3x + 4
2) 4y - 7x = 16 -> 4y = 7x + 16 -> y = 7/4x + 4
Graph A since it crosses all 4 regions of the graph
The distance between the points is 16
