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Arada [10]
3 years ago
11

Suppose that 44 identical red wooden blocks and 99 identical white wooden blocks are to be​ stacked, one on top of​ another, to

form one tall tower of blocks. How many different colour patterns can​ result?
Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

44 identical red wooden blocks can be arranged in 44! ways

99 identical white wooden blocks can be arranged in 99! Ways

If the 44 red blocks and the 99 white blocks are to be stacked on top of one another, the number of different color patterns that can​ result = 44! x 99!

 

44! = 2.65827157 x 10^54

99! = 9.33262154 x 10^155

44! x 99! = 2.48086426 x 10^210

 

Therefore, 2.48086426 x 10^210 different color patterns can ​result

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Solve: 5/2x - 1/3= -1/2<br><br>A. x=-5/12<br>B. x= -25/12<br>C. x= -1/15<br>D. x= 1/3​
devlian [24]

Answer:

c. x = -1/15

Step-by-step explanation:

5/2x - 1/3 = -1/2 [multiply the whole equation by 6 (lowest common denom)

15x - 2 = -3 [add 2 on both sides of equation

15x = -1 [divide both sides by 15 to isolate x]

x = -1/15

7 0
3 years ago
Read 2 more answers
What is the quotient
mario62 [17]

Answer:

The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer

Step-by-step explanation:

* We will use the long division to solve the problem

- The dividend is 3x² + 4x + 5

- The divisor is x + 5

- The quotient is the answer of the division

- If the divisor not a factor of a dividend, the quotient has

  a remainder

* Lets solve the problem

- At first divide the first term in the dividend by the first term in

 the divisor

∵ 3x² ÷ x = 3x

- Multiply the divisor by 3x

∴ 3x (x + 5) = 3x² + 15x

-Subtract this expression from the dividend

∴ 3x² + 4x + 5 - (3x² + 15x) = 3x² + 4x + 5 - 3x² - 15x = -11x + 5

- Divide the first term -11x in the new dividend by the first

 term x in the divisor

∴ -11x ÷ x = -11

- Multiply the divisor by -11

∴ -11(x + 5) = -11x - 55

-Subtract this expression from the new dividend

∴ -11x + 5 - (-11x - 55) = -11x + 5 + 11x + 55 = 60

∴ The quotient is 3x - 11 with remainder = 60

* The quotient is 3x - 11 + 60/(x + 5)

5 0
3 years ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
"solve each system by graphing"
garik1379 [7]
Put them into y=mx+b
y=1/3x -1 
y=2/3x-4
Graph them. Where they touch is your answer. No touch? No solution. Same line? Infinite solutions.
Second set: Same thing.
Solution to first set is (9,2)
3 0
3 years ago
What is the area of this trapezoid?
son4ous [18]
Its C)126in I think because top base is 16, bottom base is 12 and the height is 9. 

5 0
3 years ago
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