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Anna007 [38]
3 years ago
6

help please i been stuck for 2 hours........... the triangle above is a right-angled isosceles triangle. what would the measurem

ent of x have to be, given that the hypotenuse is 8cm and legs a and b have the same length? please explain your answer

Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

4√2 or 5.66

Step-by-step explanation:

x² + x² = 8²

=> 2x² = 64

=> x² = 32

=> x = √32 = 4√2 or 5.66

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Gina has 5 2/6 feet of sliver ribbon and
Alla [95]
When you convert each type of ribbon to a bigger fraction, you get 32/6 feet of silver ribbon by multiplying the denominator by the whole number then adding the numerator. you also get 16/6 feet of gold ribbon. 32-16=16 so Gina has 16 more feet of silver ribbon than gold
5 0
3 years ago
Find two consecutive even interferes such that 4 times the smaller is 18 more than 3 times the larger.
Artemon [7]

The numbers are 24 and 26

Step-by-step explanation:

  • Step 1: Let the integers be x and (x+2). Here the smaller integer is x and the larger integer is x + 2.

Given that 4x = 18 + 3(x + 2)

⇒ 4x = 18 + 3x + 6

⇒ 4x = 24 + 3x

⇒ x = 24 and x + 2 = 26

7 0
3 years ago
A chef plans to mix 100% vinegar with Italian dressing. The Italian dressing contains 12% vinegar. The chef wants to make 320 mi
EastWind [94]

Answer:

40 mL of vinegar,

280 mL of dressing

Step-by-step explanation:

Let v = the milliliters ( mL ) of 100% vinegar,

Then it should be that 320 - v = mL of dressing.

v + .12( 320 - v ) = .23( 320 ) - So in this case the mL of vinegar is associated with the percent of vinegar composed. 100 percent is, in other words, 1, and is multiplied by " v " the mL of 100% vinegar. 1 * v is also v, and so is written as such in our equation. 0.12 is the decimal form of the 12% vinegar, associated with the mL of dressing - as the italian dressing is composed of 12% vinegar. 23% is 0.23 in decimal form, multiplied by the mL of of vinegar in the mixture, 320 mL.

Let's solve for the mL of 100% vinegar, subtracting from 320 to receive the mL of dressing,

v + .12( 320 - v ) = .23( 320 ) - Distribute " .12 "

v + 38.4 - 0.12v = .23( 320 ) - Multiply " 0.32 " by " 320 "

v + 38.4 - 0.12v = 73.6 - Combine like terms and add / subtract

0.88v = 35.2 - Divide 0.88 on either side

v = 40 mL of vinegar,

320 - v = 320 - 40 = 280 mL of dressing

6 0
3 years ago
A farmer has some hens and goats. He counts a total of 60 eyes and 86 feet between them. How many hens does he have?.
ra1l [238]

The farmer has 17 hens.

<h3>What is a linear equation in two variables ?</h3>

An equation is linear if has highest degree of 1 and it has two variables.Generally they are in x and y.

For example -: 2x + 3y = 10

According to the given question a farmer has some hens and goats. He counts a total of 60 eyes and 86 feet between them.

Let us denote Hens by H and Goats by G.

We know both of them has 2 eyes each and we also know that a Hen has 2 legs and a Goat has 4 legs.

There fore the given data we can form two equations.

2H + 2G = 60 and 2H + 4G = 86.

Solving these two equations we have G = 13 and H = 17.

learn more more about linear equation in two variables here :

brainly.com/question/24085666

#SPJ4

3 0
2 years ago
Exponential growth/decay problem 2
lapo4ka [179]

Answer:

a) decay

b) 2,950,000

c) 0.025

d) f(x)=2950000(0.975)^x

e) 2,409,123

Step-by-step explanation:

<u>Part (a)</u>

Exponential DECAY, since the population was decreasing annually.

<u>Part (b)</u>

Initial amount = 2,950,000 people (in the year 2000)

<u>Part (c)</u>

Decay factor = 2.5% = 0.025 (in decimal form)

<u>Part (d)</u>

General form of exponential decay function:

f(x)=a(1-r)^x

where:

  • a = initial amount
  • r = rate of decay (in decimal form)
  • x = time (in years)

Given:

  • a = 2950000
  • r = 0.025

\implies f(x)=2950000(1-0.025)^x

\implies f(x)=2950000(0.975)^x

<u>Part (e)</u>

To determine the city's population in 2008:

x = 2008 - 2000 = 8

\begin{aligned}\implies f(8) & =2950000(0.975)^8\\ & = 2409123\: \sf(nearest\:whole\:number)\end{aligned}

7 0
2 years ago
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