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2 years ago

6

help please i been stuck for 2 hours........... the triangle above is a right-angled isosceles triangle. what would the measurem

ent of x have to be, given that the hypotenuse is 8cm and legs a and b have the same length? please explain your answer

1 answer:

Likurg_2 [28]2 years ago

8 0

Answer:

4√2 or 5.66

Step-by-step explanation:

x² + x² = 8²

=> 2x² = 64

=> x² = 32

=> x = √32 = 4√2 or 5.66

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(Brainliest to the person that get its right)

oksian1 [2.3K]

<h3>Answer: Choice B</h3>

c^2-2cd+d^2 = (c-d)^2

We can verify this with the following steps

(c-d)^2 = (c-d)(c-d)

(c-d)^2 = c(c-d) - d(c-d)

(c-d)^2 = c^2-cd-cd+d^2

(c-d)^2 = c^2-2cd+d^2

6 0

2 years ago

5 1/2+ 3 2/3+ 1 4/5

Mazyrski [523]

Answer:

$10\frac{29}{30}$

Step-by-step explanation:

$5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}$

Let us group the integers and the fractions.

$5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}$ = $(5+3+1)+(\frac{1}{2} +\frac{2}{3}+\frac{4}{5} )$

= $9+\frac{15+20+24}{30}$

$= 9+\frac{59}{30}$

$=9+1\frac{29}{30}$

$=10\frac{29}{30}$

7 0

3 years ago

The population of California is approximately 38,040,000. The population of Texas is about 2.606 × 107. What is the approximate

liubo4ka [24]

Answer:

The total population of these two states is:

$3.804\times \:\:10^7+2.606\times \:\:10^7\:=10^7\times \:\:6.41$

Therefore, option C is correct.

Step-by-step explanation:

The population of California is approximately 38,040,000.

The population of Texas is about 2.606 × 10⁷.

Writing the population of California i.e.38,040,000 in scientific notation by moving the decimal point 7 places to the left and dropping the 0's on the right side as they're after the decimal point now.

i.e.

38,040,000 = 3.804 x 10⁷

So adding 3.804 x 10⁷ and 2.606 × 10⁷

i.e.

$3.804\times \:10^7+2.606\times \:10^7$

$\mathrm{Add\:similar\:elements:}\:10^7\times \:3.804+10^7\times \:2.606=10^7\times \:6.41$

Thus, the total population of these two states is:

$3.804\times \:\:10^7+2.606\times \:\:10^7\:=10^7\times \:\:6.41$

Therefore, option C is correct.

4 0

3 years ago

If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm

natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

$F= ke$

where F is the applied force in N

k is the spring constant N/m

e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= $\frac{15}{100}$ = $0.15m$

we can solve for the spring constant k

we also know that the force F = mg

assuming $g=9.81m/s^{2}$

therefore

$24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\$

We can use this value of k to solve for the mass that will cause an extension of $10cm= 0.1m$

$x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg$

5 0

3 years ago

A student needed to find the measure of angle b. She incorrectly said m

devlian [24]

Measure of angle b= 27°

It’s a right angle, so 90-63=27!!!!!

5 0

2 years ago

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