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3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 11 feet cubed.

Mathematics

2 answers:

Mariana [72]3 years ago

8 0

Answer:

The answer is D.

Step-by-step explanation:

Sedaia [141]3 years ago

4 0

Answer:

The Answer is D or V= 2/3(11).

Step-by-step explanation:

If the cylinder and sphere have the same height and radius, the sphere will be 2/3 the volume of the cylinder. Hence, the answer will be D.

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Complete the coordinate table for the given equation. xy = 12

Flura [38]

Answer:

Step-by-step explanation:

Given is an equation in xy as xy =12

WE are to complete the coordinate table for xy =12

Let us give different values for x and find corresponding values of y

$y=\frac{12}{x}$

Note that x or y cannot equal 0 in this

So let us give other values

x y

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3 years ago

What number must you add to complete the square?<br> x^2 + 12x = 16

dmitriy555 [2]

Answer: B. 36

The complete square is (x+6)^2. It's missing the third term, which is 36 because 6 x 6 is 36.

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3 years ago

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Which graph represents this exponential function? f(x)=3(2)^x-4

Rasek [7]

Answer:

Step-by-step explanation:

look up desmos graphing calculator and it graphs all of your equations for you. I used it all through high school.

4 0

3 years ago

How to solve this10*4 ones=_ones=_

Sergio039 [100]

Do you mean ones and tenths?

5 0

3 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

3 years ago