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Elena L [17]
3 years ago
6

How do you balance Ga(Cn)3 + Sn(BrO3)4?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
4 0
4Ga(CN)3+3Sn(BrO3)4——-3Sn(CN)4+4Ga(BrO3)3
Good luck
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Which characteristic is true of sexual reproduction but not of asexual reproduction?
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Sexual Reproduction involves two different parties

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Asexual is the opposite, so it uses no one else to reproduce

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How does radiation differ from convection? (104 points)
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What is the standard model? What can it explain?
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Two proteins interact to form a multimeric complex. When one of the proteins is mutated, there is a substantial loss of function
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<h2>4. dominant negative</h2>

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The rapid decomposition of sodium azide, NaN3, to its elements is one of the reactions used to inflate airbags: 2 NaN3 (s)  2 N
masha68 [24]

<u>Answer:</u> The amount of nitrogen gas produced is 3.864 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of NaN_3 = 6.00 g

Molar mass of NaN_3 = 65 g/mol

Putting values in equation 1, we get:

\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol

For the given chemical reaction:

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

By Stoichiometry of the reaction:

2 moles of NaN_3 produces 3 moles of nitrogen gas

So, 0.092 moles of NaN_3 will produce = \frac{3}{2}\times 0.092=0.138mol of nitrogen gas

Now, calculating the mass of nitrogen gas by using equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.138 moles

Putting values in equation 1, we get:

0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g

Hence, the amount of nitrogen gas produced is 3.864 grams

7 0
3 years ago
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