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Vesnalui [34]
3 years ago
14

Help with this please.​

Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

52.8 degree

Step-by-step explanation:

x²=1.9²+2.5²

x²=9.86

x = 3.14 this is SQ

using the sine rule :

sin90/3.14 = sinx/2.5

cross multiply

after cross multiply if you are allowed to use a calculator insert shift sin

you only use this when you want to find the unknown sine angle

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x = -3

Step-by-step explanation:

5x + 3 = 4x,

x + 3 = 0,

x = -3

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Simplify
OlgaM077 [116]

Answer:

see below

Step-by-step explanation:

\frac{x-1}{x^2-3x+2}+ \frac{x-2}{x^2-5x+6} +\frac{x-5}{x^2-8x+15}

we need to simplify that

x^2-3x+2=(x-1)(x-2)\\\\x^2-5x+6=(x-2)(x-3)\\\\x^2-8x+15=(x-3)(x-5)

so we can continue

\frac{x-1}{(x-1)(x-2)}=\frac{1}{x-2}\\\\\frac{x-2}{(x-2)(x-3)} =\frac{1}{x-3}\\\\\frac{x-5}{(x-3)(x-5)} =\frac{1}{x-3}

and we can put all together

\frac{1}{x-2}+ \frac{1}{x-3}+ \frac{1}{x-3}\\\\\frac{1}{x-2} +\frac{2}{x-3}\\\\\frac{x-3}{(x-3)(x-2)}+ \frac{2(x-2)}{(x-2)(x-3)} \\\\\frac{x-3+2x-4}{(x-3)(x-2)}\\\\\frac{3x-7}{x^2-5x+6}

3 0
3 years ago
Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!
Brums [2.3K]

Answer:

Assuming the problem asks to rotate counterclockwise: E' (0,0) F' (0,5) G' (-4,5) H' (-4,0)

If it says rotate clockwise then your points will be: E' (0,0) F' (0,-5) G' (4,-5) H' (4,0)

Step-by-step explanation:

Translate the points first by subtracting 3 from the x-coordinates of each, then subtracting 3 from the y-coordinates of each. Next, to rotate them counterclockwise about the origin 90 degrees, switch the x and y coordinates and the sign of the resulting x-coordinate. To rotate clockwise 90 degrees switch the x and y still but change the sign of the resulting y coordinate.

4 0
3 years ago
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