A point is randomly chosen in the diagram shown below.
2 answers:
Answer:
The likelihood that a point chosen inside the square will also be inside the circle: 78.54%
Step-by-step explanation:
- Let x is the side of the suqare
=> the area of the square is:
- Let d is the diameter of the circle
=> the area of the circle : π
However, d=x because of the square property
<=> the area of the circle : π
The likelihood that a point chosen inside the square will also be inside the circle:
the area of the circle / the area of the square
= π /
= π *100%
= 0.7854 * 100%
= 78.54%
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That's a 33% increase.
I calculated this using the formula:
Where n = the new value (16 in your question), o = the old value (12 in your question) and the result is outputted as a percent increase. You can check that this is correct by finding 33% of 12, adding the result to 12, and checking that the result equals your "new" number.
Note that 33% is only an approximation as your question requires a number rounded to the nearest whole.
I calculated this using the formula:
Where n = the new value (16 in your question), o = the old value (12 in your question) and the result is outputted as a percent increase. You can check that this is correct by finding 33% of 12, adding the result to 12, and checking that the result equals your "new" number.
Note that 33% is only an approximation as your question requires a number rounded to the nearest whole.