Answer:
There will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days
Step-by-step explanation:
The given parameters are;
The half life of the radioactive substance = 45 days
The mass of the substance initially present = 6.2 grams
The expression for evaluating the half life is given as follows;

Where;
N(t) = The amount of the substance left after a given time period = 1 gram
N₀ = The initial amount of the radioactive substance = 6.2 grams
= The half life of the radioactive substance = 45 days
Substituting the values gives;




The time that it takes for the mass of the radioactive substance to remain 1 g ≈ 118.45 days
Therefore, there will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days.
Answer:0.2588
Step-by-step explanation:
Answer:
A = P ( 1+ r )^t ... Compound Interest
I = Prt ... Simple interest
I hope this helps you
x= 3
f (3)= 3.3^2-2= 27-2=25
g (3)= 3+7=10
f (3)-g (3)= 25-10= 15
Answer:
114
Step-by-step explanation: