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Mazyrski [523]
3 years ago
14

Sam is delivering 2 refrigerators that each weigh 105 kilograms. There is an elevator with a weight of 1000 pounds. Can he take

both refridgerators in one trip? 1 kilogram = 2.2 pounds
Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer: Yes, he can take both refrigerators in one trip .

Step-by-step explanation:

Hi, to answer this question, first, we have to convert the kilograms into pounds.

Since 1 kilogram = 2.2 pounds

105 kilograms x 2.2 pounds/kilogram= 231 pounds (1 refrigerator's weight)

Since there are 2 refrigerators, we have to multiply the weight of 1 refrigerator by 2 to obtain the total weight in pounds:

231 pounds x 2 =462 pounds

Since the elevator can lift up to 1000 pounds.

1000p>462p

He can take both refrigerators in one trip

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Answer:

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20 x 15%

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3 years ago
-8x + 2x – 16 &lt; -5x + 7x
lana [24]

Answer:

x >  2

Step-by-step explanation:

Given

- 8x + 2x - 16 < - 5x + 7x ← simplify both sides

- 6x - 16 < 2x ( subtract 2x from both sides )

- 8x - 16 < 0 ( add 16 to both sides )

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3 years ago
What is the y intercept of the function f(x)=2•3^x
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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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kvv77 [185]

Answer:

Step-by-step explanation:

Part 1

P(z < -1.45)

Using the z score table

P =

Part 2

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) P(X >52)

x = 52

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Standard deviation = 8

z = 52 - 60/8

z = -1

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5 0
2 years ago
{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

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Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
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