So....Centre coordinates are ((-3+1)÷2 ; (2+6)÷2) = (-1;4)
Calculate the radius of the circle....
Radius = square root of [(-1+3)^2 + (4-2)^2]
;Radius = square root of 8
Then substitute the x-coordinate of the centre into the first slot....then the y-coordinate into the second slot and the radius(squared) into last slot of the equation......;
Let x be the measure of both legs since the given is an isosceles right triangle. By the Pythagorean theorem we calculate for the legs, x² + x² = (5 sqrt 6)² The value of x from the given equation is approximately 8.66 units.
