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Ymorist [56]
3 years ago
10

Volume of a cylinder with radius r and height h is

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

h = \frac{v}{\pi r^{2} }

Step-by-step explanation:

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Given that QT is an altitude of triangle QRS, measure of angle QTS=(6x+36), and QR = 2x – 5, find QR.
Alexeev081 [22]
We know that
if <span>QT is an altitude of triangle QRS
then
</span><span>the measure of angle QTS is equal to 90</span>°
so
6x+36=90-----> 6x=90-36----> x=54/6
x=9
QR=2x-5-----> QR=2*9-5-----> QR=18-5-----> QR=13

the answer is
QR=13
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3 years ago
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This is due tonight pls
Anettt [7]

Answer:

I think it's A.3

Step-by-step explanation:

if you didvide the 7.8 by 2.6 then you will get 3, therfore you will have to multiply the original (2.6) times 3 in order to get the scaled image (7.8).

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Select all of the possible degrees of this polynomial function<br> 2<br> 3<br> 4<br> 5
Dafna1 [17]

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Step-by-step explanation:

6 0
3 years ago
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Factor.<br> x^2– 14x + 24
SpyIntel [72]

Answer:

(x - 2) (x - 12)

Step-by-step explanation:

Factor the following:

x^2 - 14 x + 24

The factors of 24 that sum to -14 are -2 and -12. So, x^2 - 14 x + 24 = (x - 2) (x - 12):

Answer: (x - 2) (x - 12)

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Find sin θ and cos θ if tan θ= 1/4 and sin 0&gt;0.
Serga [27]

Answer:

\displaystyle \sin(\theta)= \frac{\sqrt{17}}{17}

\displaystyle \cos(\theta)= \frac{4 \sqrt {17} }{ 17 }

Step-by-step explanation:

We want to find sin(θ) and cos(θ) given that tan(θ) = 1/4 and sin(θ) > 0.

First, since tan(θ) and sin(θ) are both positive, cos(θ) must be positive as well.

Recall that tangent is the ratio of the opposite side to the adjacent side.

Therefore, the hypotenuse is:

h=\sqrt{4^2+1^2}=\sqrt{16+1}=\sqrt{17}

So, with respect to θ, the opposite side is 1, the adjacent is 4, and the hypotenuse is √17.

Then it follows that:

\displaystyle \sin(\theta)=\frac{1}{\sqrt{17}} = \frac{\sqrt{17}}{17}

And that:

\displaystyle \cos(\theta)= \frac{4}{\sqrt{17}} = \frac{4 \sqrt {17} }{ 17 }

5 0
3 years ago
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