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yaroslaw [1]
4 years ago
13

Solve k(h-j)+h with h=5 ,j= -4, k=5

Mathematics
1 answer:
kifflom [539]4 years ago
5 0
They gave you an eqution with variables and then they gave you numbers that all you have to do is put in
k(h-j)+h
5(5-4)+5
5(1)+5
5+5
10
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Which is the graph of -5h + 3 &lt; -7?
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Write an expression for the given situation.
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I am not sure if this is right...

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7 0
3 years ago
Suppose a ball is dropped from a height of 16 feet. Each time it drops h feet, it rebounds 0.81h feet. Find the total distance t
Roman55 [17]
When the ball is first dropped, it falls h feet. On the first bounce, it rebounds 0.81h feet, which means on the second "drop" it must travel 0.81h feet again. On the second bounce, the ball rebounds 0.81(0.81h)=0.81^2h feet, and on the third drop falls the same distance. And so on.

So there are two directions to track:

\text{downward: }\displaystyle h+0.81h+0.81^2h+\cdots=\sum_{n=0}^\infty 0.81^nh
\text{upward: }\displaystyle 0.81h+0.81^2h+\cdots=\sum_{n=1}^\infty 0.81^nh

The total distance is the sum of these two:

\displaystyle\sum_{n=0}^\infty 0.81^nh+\sum_{n=1}^\infty 0.81^nh=h+2h\sum_{n=1}^\infty 0.81^n

Recall that for an infinite geometric sum, you have

\displaystyle\sum_{n=0}^\infty r^n=1+\sum_{n=1}^\infty r^n=\frac1{1-r}

provided that |r|. So the total distance traveled by the ball is

h+2h\left(\dfrac1{1-0.81}-1\right)\approx9.53h

Starting with a height of h=16 means the total distance is about 152.42 ft.
4 0
3 years ago
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