Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
ONO THAT NOT THE ANSWER THIS IS [3,628,800] 10P10=10, AND 0!= 10 TIMES 9 TIMES 8 TIMES 7 TIMES 6 TIMES 5 TIMES 4 TIMES 3 TIMES 2 TIMES 1= 3,628,800.
If you are trying to find the answer for x it would 20
Answer:
9 minutes
Step-by-step explanation:
60=15+5t
45=5t : subtract 15 from both sides
9=t : divide by 5 for both side
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