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3 years ago

7

Identify the distance between the points (9,7,3) and (5,3,2), and identify the midpoint of the segment for which these are the e

ndpoints. Round to the nearest tenth, if necessary.

1 answer:

Daniel [21]3 years ago

8 0

Answer:

<em>dggkydkyrmhxmfjiildtlitslursusappurshfufzppufpu7sritstisitsuprspursur74s</em>

Step-by-step explanation:

she will is has p7w407wsdddfduufuur5e

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Please help with this question

zalisa [80]

Answer:

4cm^2

Step-by-step explanation:

First we need to find the length of the height of the triangle using Pythagoras:

a^2+b^2=c^2 (Substitute in what we have)

a^2+3√2(^2)=2√5(^2) = a^2 + 18 = 20 -> 20-18=2 √2=BD

Now we can find the area:

AD+DC= 3√2 + √2 = 4√2 x √2 = 8/2 = 4

6 0

3 years ago

Add 3 5/12 + 2 5/9 . Simplify the answer and write as a mixed number.

Kipish [7]

5 35/36, solving steps attached below

3 0

3 years ago

A shirt is on sale for 30% off. The expression p - 0.30p, where p is the original cost of the shirt, can be used to find the sal

Law Incorporation [45]

Answer: 0.70

Step-by-step explanation the same as decreased by 30%" would be (1.00 - 0.30)(original cost), or 0.70(original cost)

3 0

3 years ago

What is <br>1.63 x 0.98 =

yarga [219]

Answer:

1.5974

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t

ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

$P_0=6.4million$

we can use formula

$P(t)=P_0 e^{rt}$

we can plug value

$P(t)=6.4 e^{rt}$

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

$7.3=6.4 e^{r*5}$

$r=0.02632$

now, we can plug back

$P(t)=6.4 e^{0.02632t}$

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

$1000=6.4 e^{0.02632t}$

$t=191.924$

approximately

$t=192$

Year is 2000+192

year is 2192................Answer

4 0

3 years ago