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2 years ago

What are the two ratios that are equivalent to 2:9

Mathematics

1 answer:

Lisa [10]2 years ago

7 0

Answer:

18:81 12:54

Step-by-step explanation:

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Three times a number minus 2 is 25. What is the number?

Verizon [17]

3×9=27-2=25
3× what # - 2= 25

7 0

2 years ago

Read 2 more answers

What two numbers multiply to 30 and add to -17

victus00 [196]

Answer:

-15 and -2

Step-by-step explanation:

Since a negative times a negative equals a positive, but when added, still stays a negative, the factors must both be negative.

Negative Factors of 30:

-30 + -1 = -31

-15 + -2 = -17

-10 + -3 = -13

-6 + -5 = -11

The two factors of 30 that add up to -17 are -15 and -2.

Hope this helps. Have a nice day.

4 0

2 years ago

If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

castortr0y [4]

$6x^2+x-2=6x^2+4x-3x-2=2x(3x+2)-1(3x+2)\\\\=(3x+2)(2x-1)\\\\3x+2=0\to x=-\frac{2}{3}\\\\2x-1=0\to x=\frac{1}{2}\\\\\alpha=-\frac{2}{3};\ \beta=\frac{1}{2}\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{-\frac{2}{3}}{\frac{1}{2}}+\frac{\frac{1}{2}}{-\frac{2}{3}}=-\frac{2}{3}\cdot\frac{2}{1}-\frac{1}{2}\cdot\frac{3}{2}=-\frac{4}{3}-\frac{3}{4}\\\\=-\frac{16}{12}-\frac{9}{12}=-\frac{25}{12}=-2\frac{1}{12}$

$use\ Vieta's\ formula:\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\\\\\alpha+\beta=\frac{-b}{a};\ \alpha\beta=\frac{c}{a}\\\\\frac{(\alpha+\beta)^2}{\alpha\beta}-2=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2=\frac{b^2}{a^2}\cdot\frac{a}{c}-2=\frac{b^2}{ac}-2$

$6x^2+x-2\\\\a=6;\ b=1;\ c=-2\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{1^2}{6\cdot(-2)}-2=\frac{1}{-12}-2=-2\frac{1}{12}$

7 0

2 years ago

Which of the following is a solution to the inequality below?

BaLLatris [955]

I did the math but I got -4 so maybe -14

6 0

2 years ago

Read 2 more answers

Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC

RoseWind [281]

Answer:

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = $\sqrt{320}$

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² = 24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = $\frac{640.41}{32}$

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0

2 years ago