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3 years ago

How can you visually display data to show a relationship between two variables? Help

Mathematics

1 answer:

KengaRu [80]3 years ago

4 0

Answer:

you can use a venn diagram

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Can somebody help me with this problem .. I’ll really appreciate it .

Ira Lisetskai [31]

Answer:

4(4x+3)=19x+9-3x+3

4*4x 4*4 =19x+9-3x+3

16x+12= 16x+12

12=12

8 0

3 years ago

Evaluate b - 2 a - c for a = -3, b = 9, and c = -6

saw5 [17]

9-2(-3)+6= 9+6+6 Your answer should be 21 if I read your question correctly

3 0

3 years ago

Read 2 more answers

M - 37 = 56<br> jack has 56 marbles Kyle has 37 fewer than jack

Goshia [24]

Do we have to solve for M if so, the answer is

m-37 = 56

m =56 + 37

m = 93

hope it's helpful

8 0

3 years ago

Please help me?i don’t want to fail

Kobotan [32]

Answer:

-4x-(-5x)=1

the slope is 6

you start at the 0 axis and go up 3 on the y.Once you did that you want to go up 2 on the y axis then 3 to the right on the x axis,then go up 2 then 3 to the right.

Step-by-step explanation:

8 0

2 years ago

The equation h = -16t 2+ 53x + 8 gives the height h, in feet, of a football as a function of time t, in seconds, after it is kic

Elanso [62]

Answer: The maximum height the football reaches = 51.89 feet.

Step-by-step explanation:

Given: The equation $h = -16t^2+ 53t + 8$ gives the height h, in feet, of a football as a function of time t, in seconds, after it is kicked.

Differentiate the given equation, we get

$h'=-(2)16t+53=-32t+53$ (i)

Put $h'=0$

$\Rightarrow\ -32t+53=0\\\\\Rightarrow\ t=\dfrac{53}{32}\approx1.65625$

Differentiate (i) w.r.t. t, we get

$h''=-32$ < 0 i.e. h is maximum at t= 1.65625

The value of h at t= 1.65625 will be $-16(1.65625)^2+53(1.65625)+8=51.890625\approx51.89\text{ feet}$

Hence, the maximum height the football reaches = 51.89 feet.

8 0

3 years ago