First off, your chances of red are not really 50-50. You are overlooking the 0 slot or the 00 slot which are green. So, chances of red are 18 in 37 (0 slot) or 38 (0 and 00 slots). With a betting machine, the odds does not change no trouble what has occurred before. Think through the simplest circumstance, a coin toss. If I toss heads 10 times one after the other, the chances of tails about to happen on the next toss are still on a 50-50. A betting machine has no ability, no plan, and no past.
Chances (0 slot) that you success on red are 18 out of 37 (18 red slots), but likelihoods of losing are 19 out of 37 (18 black plus 0). For the wheel with both a 0 and 0-0 slot, the odds are poorer. You chances of red are 18 out of 38 (18 red slots win), and down are 20 out of 38 (18 black plus 0 and 00). It does not really matter on how long you play there, the probabilities would always continue the same on every spin. The lengthier you play, the more thoroughly you will tie the chances with a total net loss of that portion of a percent in accord of the house. 18 winning red slots and either 19 or 20 losing slots.
Start off by using the Pythagorean Theorem: a^2 + b^2 = c^2
12^2 + 35^2 = 37^2
144 + 1,225 = 1,369
1,369 = 1,369
If the left side equals the right side than it is a right triangle.
Your answer is: Yes
Have an amazing day and stay hopeful!
The probability from 1.5 ≤ x ≤ 3 can be calculated by dividing the Area from x=1.5 to x=3 by the total Area of the distribution.
The given distribution is rectangular shaped, so its Area will be = Length x Width = 1 x 3 = 3 square units
From x = 1.5 to x = 3, the length is 1.5 and width is 1. So the area between these two intervals = 1.5 square units.
Thus, <span>P(1.5 ≤ X ≤ 3) = 1.5/3 = 0.5
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Answer:
1.5974
Step-by-step explanation:
Answer: G
Step-by-step explanation: the rate of change is constant, making it a proportional relationship