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storchak [24]
3 years ago
7

The positions on a lacrosse team are called defenders (D), midfielders (M), and attackers (A). One player is chosen at random to

lead the team in
exercises before each game. The letters MDD mean that a midfielder was chosen at the first game and a defender was chosen at the next two
games. The list of all possible outcomes is shown, where each outcome has equal probability of occurring.
AAA AMA ADA
MAA
MDA DAA DMA DDA
AAM AMM ADM MAM MMM MDM
DMM DDM
AAD AMD ADD MAD MMD MDD DAD DMD DDD
MMA
DAM
What is the probability that a defender is chosen at least once, given that a midfielder is chosen at the first game?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer: DAM

Step-by-step explanation:

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Answer:

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Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

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The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

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Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

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The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

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The present percentage of pure alcohol in the solution, C%₂ = 72.25%

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