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nirvana33 [79]
3 years ago
7

A company president flew 990 miles in a corporate jet but returned in a smaller plane that could fly only half as fast. If the t

otal travel time was 9 hours, find the speeds of the planes. corporate jet ________ mph smaller plane ________ mph
Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

I'm not completely sure but I think the answer is:

corporate jet 16.5 mph

smaller plane 33 mph

Good luck

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The given line segment has a midpoint at (−1, −2).
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The given line segment has a midpoint at (−1, −2).

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150 people are in a movie theater to see Wonder Woman. If 7 out of 30 of them are boys how many boys are there?
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2 years ago
2 right triangles have identical angle measures but different side lengths. The first triangle has side lengths of 6, 10, 8 and
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7 0
3 years ago
Given s left parenthesis t right parenthesis equals 5 t squared plus 5 ts(t)=5t2+5t​, find
finlep [7]

Answer:

The velocity function is v(t)=10t+5.

The acceleration function is a(t)=10.

When t = 44​, the velocity is v(44)=445 \:\frac{ft}{s}.

When t = 44​, the acceleration is a(44)=10\: \frac{ft}{s^2}.

Step-by-step explanation:

We know that the position function is given by

s(t)=5t^2+5t

Velocity is defined as the rate of change of position or the rate of displacement. If you take the derivative of the position function you get the instantaneous velocity function.

v(t)=\frac{ds}{dt}

Acceleration is defined as the rate of change of velocity. If you take the derivative of the instantaneous velocity function you get the instantaneous acceleration function.

a(t)=\frac{dv}{dt}

The instantaneous velocity function is given by

v(t)=\frac{d}{dt} s(t)=\frac{d}{dt}(5t^2+5t)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(5t^2\right)+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\v(t)=10t+\frac{d}{dt}\left(5t\right)\\\\\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dt}\left(t\right)=1\\\\v(t)=10t+5

The instantaneous acceleration function is given by

a(t)=\frac{dv}{dt} =\frac{d}{dt}(10t+5)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\a(t)=\frac{d}{dt}\left(10t\right)+\frac{d}{dt}\left(5\right)\\\\a(t)=10

To find the velocity and acceleration when t = 44, we substitute this value into the velocity and acceleration functions

v(44)=10(44)+5\\v(44)=445 \:\frac{ft}{s}

a(44)=10\: \frac{ft}{s^2}

6 0
3 years ago
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