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ELEN [110]
3 years ago
14

PLZ HELP SUPER EASY I'M JUST HELLA DU.MB

Mathematics
1 answer:
laiz [17]3 years ago
7 0

Answer:

I can't answer that if there is no picture, I'm sorry

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Which equation can be used to solve for c?
AlladinOne [14]
From the given triangle in the photo, the lengths of the sides are 3m and a, the hypotenuse is c. One angle, opposite of 3m is given to be 50 degrees C. The right equation that would solve c is,
                                         sin (50 degrees C) = 3m / c
Thus, the answer is the first choice. 
5 0
4 years ago
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Please help with this question
aalyn [17]

Answer:

4th

Step-by-step explanation:

You do the step by step process you learn in math class and subtract them

4 0
3 years ago
the distance light travels in one second (one light-second) is about 1.86 x 10^5 miles. Saturn is about 475 light-seconds from t
iris [78.8K]
The distance light travels in one second (one light second ) - 1.86 x 10^5 miles
Saturn is 475 light seconds away from the sun. Using this information we are asked to find the distance saturn is away from the sun.
1 light second - 1.86 x 10^5 miles
Therefore 475 light seconds -1.86 x 10^5 miles/light second * 475 light seconds 
                                             = 8.83 x 10^7 miles
Saturn is 8.83 x 10^7 miles away from the sun
7 0
4 years ago
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HELP PLEASE <br><br> Solve for h.<br><br> −110=13+3(4h−6)
Tems11 [23]

Answer: h=-8.75, h=-35/4, h=-8 3/4

Step-by-step explanation:

Multiply parentheses by three, calculate, move terms, calculate, divide both sides by 12

3 0
3 years ago
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Please, i need help with the spider in the box question
Andrej [43]

Answer:

AB=5.39 cm

BC=5 cm

CD=5.83 cm

DE=3.91 cm

A to E=20.13 cm

Step-by-step explanation:

DE^2=2.5^2+3^2

DE^2=6.25+9

DE^2=15.25

DE=3.91

CD^2=3^2+5^2

CD^2=9+25

CD^2=34

CD= 5.83

BC^2=4^2+3^2

BC^2=16+9

BC^2=25

BC=5

AB^2=5^2+2^2

AB^2=25+4

AB^2=29

AB=5.39

5.39+5+5.83+3.91=20.13

5 0
3 years ago
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