It would just be the tot foot time the cost
7.5 X 0.50 = $3.75
For there to be 1 car, we consider two possible outcomes:
The first door opened has a car or the second door opened has a car.
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For there to be no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
Probability of at least one car is the sum of the probability of one car and probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
<h2>The third graph</h2><h3 /><h3>The graph has a slope of 2</h3><h3>and a y-intercept of -4</h3>
Answer:
no one of them has to be 90 degrees
Step-by-step explanation:
