Answer:
74 g/mol
Explanation:
Using a periodic table, we can determine the molar mass by adding together 1 Ca, 2 O, and 2 H. This turns out to be approximately (40+32+2) = 74 g/mol
On the cumulative Report, it would be much easier to read for the patients if the ranges in parentheses were tabbed over from the actual result instead of printing directly one space after the result.
sp3d2 hybridization has 1s, 3p and 2d orbitals, that undergo intermixing to form 6 identical sp3d2 hybrid orbitals. These 6 orbitals are directed towards the corners of an octahedron. They are inclined at an angle of 90 degrees to one another.
<h3>Which orbitals hybridize to form hybrid orbitals?</h3>
For each carbon, one 2s orbital and two 2p orbitals hybridize to form three sp2 orbitals. These hybridized orbitals align themselves in the trigonal planar structure. For each carbon, two of these sp orbitals bond with two 1s hydrogen orbitals through s-sp orbital overlap.
<h3 /><h3>What is sp3d2 hybridization?</h3>
Intermixing of one 's', three 'p' and two 'd' orbitals of almost same energy by giving six identical and degenerate hybrid orbitals is called sp3d2 hybridization. These six sp3d2 orbitals are arranged in octahedral symmetry by making 90° angles to each other.
Learn more about hybridization here:
<h3 /><h3>
brainly.com/question/1604211</h3><h3 /><h3>#SPJ4</h3>
1st you pour the mixture<span> through a filter to remove the larger </span>pebbles<span>. Next, add water to dissolve the salt and then filter out the </span>pepper the last thing you do <span>evaporate the water to leave the salt behind.</span>
<u>Answer:</u>
<em>The mineral we are talking about here is olivine.</em>
<u>Explanation:</u>
It is a bit dark in color which ranges between yellow to Green to olive green. The luster present in it is nonmetallic luster but has a glassy finish and a substance hardness that is ranging between 6.5 to 7.
This mineral has granular masses which we can say has mass like sugar grains. This mineral has cleavage with conchoidal fracture present in it.