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3 years ago

A gas with an empirical formula C2H2O has a molecular weight of 120.6g/mol. A possible molecular formula for the gas is

Chemistry

1 answer:

Virty [35]3 years ago

7 0

M(C2H2O)= 12.0*2 +1.0*2 +16.0 = 42 g/mol is a molar mass for empirical formula.

120.6g/mol/42g/mol ≈ 3

So, empirical formula should be increased 3 times,

and molecular formula is C6H6O3.

Answer is D.

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The density of water is about 1.0 g/mL at room temperature. Briefly explain how the density of an aqueous solution at room tempe

maksim [4K]

Answer:

The density of water is about 1.0 g/mL at room temperature.

Briefly explain how the density of an aqueous solution at room temperature can be significantly less than 1.0 g/mL.

Give an example of such a solution.

Explanation:

That means 1.0mL of water weighs ---- 1.0g

If any other aqueous solution which has mass less than 1.0g will have density less than 1.0g.

For example aqueous solution of sulfuric acid has density 0.98g/mL.

That means 1mL of sulfuric acid has mass 0.98g.

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3 years ago

Kinetic Energy Problems = KE = 0.5m x 12

Brut [27]

Explanation:

The kinetic energy of an object is given by :

$K=\dfrac{1}{2}mv^2$

1. Mass, m = 5 kg

Speed, v = 2 m/s

$K_1=\dfrac{1}{2}\times 5\times (2)^2\\\\=10\ J$

2. Mass, m = 71 kg

Speed, v = 1 m/s

$K_2=\dfrac{1}{2}\times 71\times (1)^2\\\\=35.5\ J$

3. Mass, m = 71 kg

Speed, v = 5 m/s

$K_3=\dfrac{1}{2}\times 71\times (5)^2\\\\=887.5\ J$

4. Mass, m = 1816 kg

Speed, v = 25 m/s

$K_4=\dfrac{1}{2}\times 1816\times (25)^2\\\\=567500\ J$

8 0

3 years ago

How many water molecules are need to break down an oligosaccharide that contains 10 glucose units?

mestny [16]

Answer is 10 units of water molecules.

3 0

3 years ago

Choose the correct answer from the options given.

Pavel [41]

Answer: 1 part is sulfuric acid is a catalyst

2 part is vanadium (V) oxide is a catalyst

Explanation:

4 0

3 years ago

Some antacid tables contain aluminum hydroxide. The aluminum hydroxide reacts with stomach acid according to the equation: Al(OH

MatroZZZ [7]

Answer:

26.67 mol HCl

Explanation:

Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O

In order to solve this problem, we need to c<u>onvert Al(OH)₃ moles to HCl moles</u>.

To do so we use the<em> stoichiometric ratios</em> of the balanced reaction:

8.89 mol Al(OH)₃ * $\frac{3molHCl}{1molAl(OH)_{3}}$ = 26.67 mol HCl

Thus 26.67 moles of HCl would react completely with 8.89 moles of Al(OH)₃.

4 0

3 years ago