Answer:
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The mass of pentane the student should weigh out is
The density of pentane is 0.626 gcm-3
To calculate the mass of pentane following expression is used,
(Density is defined as the mass divide by volume)
Density = mass / volume
mass of pentane = Density of pentane * Volume of pentane
mass of pentane = 0.626 gcm-3 * 45.0 mL
= 28.17 g
Here the unit of mass of pentane is g,
However the unit of density is gcm-3 and unit of volume is mL i.e. cm3
Hence, Mass = gcm-3 * cm3
Mass = g
The mass of pentane the student should weigh out is 28.17g
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Answer:
4.43L is final volume of the ballon
Explanation:
Avogadro's law of ideal gases states that <em>equal volumes of gases, at the same temperature and pressure, have the same number of molecules</em>.
The formula is:
Where V and n are volume and moles of the gas in initial and final conditions.
If the initial conditions are 0.0145 moles and 2.54L and final amount of moles is 0.0253moles, final volume is:
V₂ = <em>4.43L is final volume of the ballon</em>
Explanation:
Use the density formula to determine the volume of the piece of metal.
density
=
mass
volume
Rearrange the equation to isolate volume.
volume
=
mass
density
volume
=
147
g
7.00
g
mL
=
21.0 mL
The final volume in the cylinder after adding the piece of metal is
20.0 mL
+
21.0 mL
=
41.0 mL
