Answer:
6.38×10²¹ molecules
Explanation:
Formula for molybdenum chloride is:
Mo₂Cl₁₀
Molar mass is : (Molar mass for Mo) . 2 + (Molar mass for Cl) . 10
95.94 . 2 + 35.45 . 10 = 546.38 g/mol
We determine moles that are contained in 5.790 g of Mo₂Cl₁₀
5.790 g . 1 mol /546.38 g = 0.0106 moles
We count the molecules: 0.0106 mol . 6.02×10²³ molecules / mol =
6.38×10²¹ molecules
Remember that 6.02×10²³ is also called Avogadro's number (NA) which is the number of particles of anything, that are contained in 1 mol.
Assuming that the reaction proceeds, the reaction would be a double displacement reaction.
BaCl2 + 2NH4CH3COO -> Ba(CH3COO)2 + 2NH4Cl
If the reaction occurs in an aqueous solution, the products are soluble in water, so the reaction is probably not that interesting to look at.
Answer:
The new partial pressures after equilibrium is reestablished for
:

The new partial pressures after equilibrium is reestablished
:

The new partial pressures after equilibrium is reestablished for
:

Explanation:

At equilibrium before adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
The expression of an equilibrium constant is given by :


At equilibrium after adding chlorine gas:
Partial pressure of the 
Partial pressure of the 
Partial pressure of the 
Total pressure of the system = P = 263.0 Torr




At initail
(13.2) Torr (32.8) Torr (13.2) Torr
At equilbriumm
(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr


Solving for x;
x = 6.402 Torr
The new partial pressures after equilibrium is reestablished for
:

The new partial pressures after equilibrium is reestablished
:

The new partial pressures after equilibrium is reestablished for
:
