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anygoal [31]
3 years ago
7

Which of the following are considered pure substances?

Chemistry
2 answers:
PolarNik [594]3 years ago
5 0

A. element

and B. compound because they are both considered pure substances

Brut [27]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

A pure substance is defined a substance that contains atoms of same element and it has constant composition throughout the sample.

For example, sulfur, H_{2}, nitrogen etc are all pure substances.

Whereas a compound is a substance that contains two or more substances which are combined together in a fixed composition.

For example, NaCl is a compound.

When components of solute are uniformly distributed in a solvent then the solution is known as homogeneous solution.

When components of solute are non-uniformly distributed in a solvent then the solution is known as heterogeneous solution.

Thus, we can conclude that elements are considered pure substances.

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It is easier to determine the electron configurations for the p-block elements in periods 1, 2, and 3 than to determine the elec
babymother [125]

Answer:

Their electrons are placed in a higher number of orbitals

Explanation:

  • Suppose a element be Ga .

The atomic no is 31

The configuration is given by

\\ \sf\longmapsto 1s^22s^22p^63ss^23p^63d^{10}4s^24p^1

Or

\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1

5 0
3 years ago
Which of the following is an electrolyte?
brilliants [131]

Answer: A

Explanation:

7 0
2 years ago
Besides hydrogen and oxygen what is required to produce the chemical reaction that yields water
timurjin [86]
Hey there! Hello!

In order for water to be formed, or for any reaction to occur, there needs to be something that splits the current bonds of hydrogen and oxygen up. In this case, some sort of activation energy is required. 

Hydrogen and oxygen are not found as single molecules in nature. They're found as 2 molecules linked together, as H2 and O2. An activation energy, such as heat, or some sort of catalyst needs to be used in order to split the two molecules up and make them link with one another. 

What happens afterwards is a chemical reaction that involves the valence electrons of oxygen (which has 6 on the outermost shell) and hydrogen (which has two on the outermost shell). The oxygen wants to have an octet (8 valence electrons) total, so it shares with the hydrogen, which is already satisfied with it's two valence electrons (according to the nature of hydrogen). 

But because there has to be a total of four molecules involved, two molecules of water are going to be produced as a result. 

2H+2O=2H20

Hope this helped you out! Feel free to ask me any additional questions if you need further clarification. :-)
3 0
3 years ago
If someone gave you flour, sugar, butter, eggs, baking soda, and salt, what could those ingredients turn into?
iren [92.7K]

Answer:

You can make Cake CAke Cake Cake and other stuff too Ig

Explanation:

4 0
3 years ago
The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
Kay [80]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

6 0
3 years ago
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