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anygoal [31]
3 years ago
7

Which of the following are considered pure substances?

Chemistry
2 answers:
PolarNik [594]3 years ago
5 0

A. element

and B. compound because they are both considered pure substances

Brut [27]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

A pure substance is defined a substance that contains atoms of same element and it has constant composition throughout the sample.

For example, sulfur, H_{2}, nitrogen etc are all pure substances.

Whereas a compound is a substance that contains two or more substances which are combined together in a fixed composition.

For example, NaCl is a compound.

When components of solute are uniformly distributed in a solvent then the solution is known as homogeneous solution.

When components of solute are non-uniformly distributed in a solvent then the solution is known as heterogeneous solution.

Thus, we can conclude that elements are considered pure substances.

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1. In 1996 a meteor crashed into the Earth near Steelsville, Ontario. The resulting meteorite was found to contain 5,790 g of Mo
wlad13 [49]

Answer:

6.38×10²¹ molecules

Explanation:

Formula for molybdenum chloride is:

Mo₂Cl₁₀

Molar mass is : (Molar mass for Mo) . 2 + (Molar mass for Cl) . 10

95.94  . 2 + 35.45  . 10 = 546.38 g/mol

We determine moles that are contained in 5.790 g of Mo₂Cl₁₀

5.790 g . 1 mol /546.38 g = 0.0106 moles

We count the molecules:  0.0106 mol . 6.02×10²³ molecules / mol =

6.38×10²¹ molecules

Remember that 6.02×10²³ is also called Avogadro's number (NA) which is the number of particles of anything, that are contained in 1 mol.

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3 years ago
What is the name of the compound cs (mno4)2
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D. cadmium permangantie
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1. Suppose you had 58.44 grams of NaCl and you dissolved it in exactly 2.00 L of solution.
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2 years ago
How to balance an ionic equation BaCl2 + 2NH4CH3COO
Lorico [155]
Assuming that the reaction proceeds, the reaction would be a double displacement reaction. BaCl2 + 2NH4CH3COO -> Ba(CH3COO)2 + 2NH4Cl If the reaction occurs in an aqueous solution, the products are soluble in water, so the reaction is probably not that interesting to look at.
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3 years ago
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective
djverab [1.8K]

Answer:

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=P_1=13.2 Torr

Partial pressure of the Cl_2=P_2=13.2 Torr

Partial pressure of the PCl_5=P_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=\frac{P_1}{P_1\times P_2}

=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=P_1'=13.2 Torr

Partial pressure of the Cl_2=P_2'=?

Partial pressure of the PCl_5=P_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=P_1'+P_2'+P_3'

263.0Torr=13.2 Torr+P_2'+217.0 Torr

P_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=\frac{P_3'}{P_1'\times P_2'}

1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

5 0
3 years ago
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