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anygoal [31]
2 years ago
7

Which of the following are considered pure substances?

Chemistry
2 answers:
PolarNik [594]2 years ago
5 0

A. element

and B. compound because they are both considered pure substances

Brut [27]2 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

A pure substance is defined a substance that contains atoms of same element and it has constant composition throughout the sample.

For example, sulfur, H_{2}, nitrogen etc are all pure substances.

Whereas a compound is a substance that contains two or more substances which are combined together in a fixed composition.

For example, NaCl is a compound.

When components of solute are uniformly distributed in a solvent then the solution is known as homogeneous solution.

When components of solute are non-uniformly distributed in a solvent then the solution is known as heterogeneous solution.

Thus, we can conclude that elements are considered pure substances.

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Exothermic and H=-1.55x10^6

Explanation:

Because the water is changing it is exothermic and the h is also exothermic

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What happens when an atom of sulfur combines with two atoms of chlorine to produce SCl2?
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Answer:

Each chlorine atom shares a pair of electrons with the sulfur atom. ... Each chlorine atom shares all its valence electrons with the sulfur atom

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3 years ago
QUESTION 1: Using the experimental data, calculate the standard reduction potential for each metal, and organise them into a sta
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What effect would a decrease or increase in barometric pressure have on the boiling point
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Pressure Affects the Boiling Point

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3 years ago
SOMEONE PLEASE HELP
Zinaida [17]

Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

1 kg= 1000g

1m³= 1 ×10⁶ cm³

Mass of iron bar

= 64.2g

= 64.2 ÷1000 kg

= 0.0642 kg

Volume of iron bar

= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

=  \frac{0.0642}{8.16 \times 10^{ - 6} }

= 7870 kg/m³ (3 s.f.)

7.

\boxed{mass = density \:  \times volume}

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

Mass of brick

= 151 g

= 151 ÷ 1000 kg

= 0.151 kg

Density of brick

= mass ÷ volume

=  \frac{0.151} {1.25 \times 10^{ - 5} }  \\  = 12600 \: kg/ {m}^{3}

(3 s.f.)

6 0
3 years ago
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