Answer:
Their electrons are placed in a higher number of orbitals
Explanation:
- Suppose a element be Ga .
The atomic no is 31
The configuration is given by

Or
![\\ \sf\longmapsto [Ar]3d^{10}4s^24p^1](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5BAr%5D3d%5E%7B10%7D4s%5E24p%5E1)
Hey there! Hello!
In order for water to be formed, or for any reaction to occur, there needs to be something that splits the current bonds of hydrogen and oxygen up. In this case, some sort of activation energy is required.
Hydrogen and oxygen are not found as single molecules in nature. They're found as 2 molecules linked together, as H2 and O2. An activation energy, such as heat, or some sort of catalyst needs to be used in order to split the two molecules up and make them link with one another.
What happens afterwards is a chemical reaction that involves the valence electrons of oxygen (which has 6 on the outermost shell) and hydrogen (which has two on the outermost shell). The oxygen wants to have an octet (8 valence electrons) total, so it shares with the hydrogen, which is already satisfied with it's two valence electrons (according to the nature of hydrogen).
But because there has to be a total of four molecules involved, two molecules of water are going to be produced as a result.

Hope this helped you out! Feel free to ask me any additional questions if you need further clarification. :-)
Answer:
You can make Cake CAke Cake Cake and other stuff too Ig
Explanation:
<u>Answer:</u> The percentage abundance of
and
isotopes are 77.5% and 22.5% respectively.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
.....(1)
Let the fractional abundance of
isotope be 'x'. So, fractional abundance of
isotope will be '1 - x'
- <u>For
isotope:</u>
Mass of
isotope = 35 amu
Fractional abundance of
isotope = x
- <u>For
isotope:</u>
Mass of
isotope = 37 amu
Fractional abundance of
isotope = 1 - x
Average atomic mass of chlorine = 35.45 amu
Putting values in equation 1, we get:
![35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775](https://tex.z-dn.net/?f=35.45%3D%5B%2835%5Ctimes%20x%29%2B%2837%5Ctimes%20%281-x%29%29%5D%5C%5C%5C%5Cx%3D0.775)
Percentage abundance of
isotope = 
Percentage abundance of
isotope = 
Hence, the percentage abundance of
and
isotopes are 77.5% and 22.5% respectively.