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ipn [44]
3 years ago
8

a mixture of gases contains He (g) and Ne (g). the total pressure of the atmosphere in the container is 600 mmHg and the partial

pressure of Ne (g) is 439 mmHg. Calculate the partial pressure of He (g) one the container.
Chemistry
1 answer:
aliina [53]3 years ago
3 0

Answer:

161 mmHg

Explanation:

Ptotal= PHe +PNe

PHe= Ptotal-PNe

PHe= (600 mm Hg)-(439 mmHg)

PHe=161 mmHg

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Approx.
15
⋅
g
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Explanation:
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F
e
2
O
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=

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⋅
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⋅
g
⋅
m
o
l
=

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⋅
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o
l
with respect to the oxide.
But by the composition of the oxide, there are thus
2
×
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⋅
m
o
l
×
55.8
⋅
g
⋅
m
o
l
−
1

iron metal

=

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