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Luda [366]
4 years ago
12

Balance the following equation in acidic conditions. Phases are optional.

Chemistry
1 answer:
NISA [10]4 years ago
4 0
I think the reaction involved here is a redox reaction in acidic conditions. To balance this type of reaction, we do as follows:

Balance the O atoms in each side by adding H2O on either side.
Balance H atoms in each side by adding H+.
Balance the charges by adding electrons.

Hope this helps.
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8KCIO3 +1C12H22011
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3.2 g KClO3

Explanation:

1.1 g C12H22O11 × (1 mol C12H22O11/342.3 g C12H22O11)

= 0.0032 mol C12H22O11

0.0032 mol C12H22O11 × (8 mol KClO3/1 mol C12H22O11)

= 0.026 mol KClO3

Therefore, the minimum amount of KClO3 needed is

0.026 mol KClO3 × (122.55 g KClO3/1 mol KClO3)

= 3.2 g KClO3

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3 years ago
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Explanation:

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3 years ago
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gregori [183]

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