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3 years ago

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This is true for the body being attracted as well. Bodies of water that are smaller than oceans, seas, and large lakes are _____

_______________ by the Moon’s gravity, but the reaction is so small that we are not able to see it.
fill in the blank:)

1 answer:

zhannawk [14.2K]3 years ago

4 0

Answer:

:)

:)

Explanation:

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Large-scale environmental catastrophes _______.

Ymorist [56]

Answer:

D. All of the Above

Explanation:

i just took the test on edgenuity

3 0

3 years ago

Calculate the energy, in joules, required to ionize a hydrogen atom when its electron is initially in the n =2 energy level. The

qaws [65]

Answer:

$E_{ionization}=5.45\times 10^{-19}\ J$

Explanation:

$E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

So, $n_i=2$ and $n_f=\infty$ (As the hydrogen has to ionize)

Thus,

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J$

$E_{ionization}=5.45\times 10^{-19}\ J$

4 0

3 years ago

An atom of element A has 108 protons. What would the elements atomic number be?

marusya05 [52]

108 is the atomic number

3 0

3 years ago

What is the pH of a 0.222 M acetic acid solution?

Oksi-84 [34.3K]

pH=2.7

<h3>Further explanation</h3>

Acetic acid = weak acid

$\tt [H^+]=\sqrt{Ka.M}$

Ka = acid ionization constant

M = molarity

Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵

$\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}$

$\tt pH=3-log~1.998=2.7$

7 0

3 years ago

At standard pressure, ammonia melts at 195 K and boils at 240 K. If a sample of ammonia at standard pressure is cooled from 200

Svetradugi [14.3K]

Answer:

I) the heat capacity of ammonia(s)

II) the heat capacity of ammonia(ℓ)

IV) the enthalpy of fusion of ammonia

Explanation:

Initially, ammonia at 200 K is liquid. To calculate the change of enthalpy from 200 K to 195 K (melting point) we need to know the heat capacity of ammonia(ℓ).

At 195, ammonia is in the transition from liquid to solid (solidification). To calculate the change of enthalpy in that process we need to know the enthalpy of solidification of ammonia, which has the same value but opposite sign to the enthalpy of fusion of ammonia.

From 195 K to 0 K, ammonia is solid. To calculate the change of enthalpy in that process we need to know the heat capacity of ammonia(s).

7 0

3 years ago