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3 years ago

What is x? 3x + 4 = 4x

Mathematics

1 answer:

e-lub [12.9K]3 years ago

3 0

Answer:

x = 4

Step-by-step explanation:

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Peanuts in bulk bins at the grocery store cost $0.30 per ounce.How much would 2 pounds of peanuts cost?

Svetach [21]

1 pound is 16 ounces so multiply by .30 to get 4.80 times 2 bc theres 2 pounds which will be $9.60

5 0

2 years ago

Walt is mixing fruit punch for a party. He combines 1 gallon 2 quarts 3 pints of orange juice 1 gallon 3 quarts 7 pints of pinea

Vlad [161]

So he's mixing:

1 gallon 2 quarts 3 pints of orange juice
1 gallon 3 quarts 7 pints of pineapple juice and
1 gallon 3 quarts 3 pints of ginger ale

that's:

3 gallons 8 quarts and 13 pints.

2 pints make a quart, so 13 pints make 6 quarts and 1 pint, so actually it's:

3 gallons 8+6=14 quarts and 1 pint.
4 quarts are a gallon, and 14 quarts are 3 gallons 2 quarts, so the final answer is:


3+3=6 gallons 2 quarts and 1 pint.

4 0

2 years ago

What is the quotient? URGENT!!

jeyben [28]

Answer:

The answer is A.

Step-by-step explanation:

You have to multiply by converting the second fraction into upside down :

$\frac{4x + 1}{6x} \div \frac{x}{3x - 1}$

$= \frac{4x + 1}{6x} \times \frac{3x - 1}{x}$

$= \frac{(4x + 1)(3x - 1)}{x(6x)}$

$= \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} }$

$= \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} }$

5 0

2 years ago

The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation

mafiozo [28]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = $\mu = 69$

Standard deviation = $\sigma = 7$

Formula : $z=\frac{x-\mu}{\sigma}$

Now At x = 55

$z=\frac{55-69}{7}$

$z=-2$

At x = 76

$z=\frac{76-69}{7}$

$z=1$

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = $0.8185 \times 100 = 81.85\%$

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

7 0

2 years ago

Which of these numbers are less than 8.1 × 10^-8?

lina2011 [118]

The answer is 3.4×10^-10

8 0

2 years ago