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Luda [366]
3 years ago
8

He graph of the function f(x) = –(x + 6)(x + 2) is shown below.

Mathematics
2 answers:
KIM [24]3 years ago
5 0
See attachment although I gather this is not your question. I did the graph(s) for the function, 

sergeinik [125]3 years ago
5 0

Answer:

<em>Which statement about the function is true?</em>

⇒ The function is increasing for all real values of x where

x < –4.

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
diamong [38]

Answer:

 A-2, B-DNE*, C-3, D-DNE, E-4, F-1

---------------------

The first attachment shows the solutions to A and C.

The second attachment shows the solutions to E and F.

There are no real number solutions to systems B and D.

_____

In general, you can solve the linear equation for y, then substitute that into the quadratic. You can subtract the x-term on the left and complete the square to find the solutions.

A.

 (3-x) +12 = x^2 +x

 15 = x^2 + 2x

 16 = x^2 +2x +1 = (x +1)^2 . . . . add the square of half the x-coefficient to complete the square; next take the square root

 ±4 -1 = x = {-5, 3) . . . . . identifies the second solution set for system A

__

B.

 (x -1) -15 = x^2 +4x

 -16 = x^2 +3x

 -13.75 = x^2 +3x +2.25 = (x +1.5)^2

roots are complex: -1.5 ±i√13.75

__

C.

 (1-2x) +5 = x^2 -3x

 6 = x^2 -x

 6.25 = x^2 -x + .25 = (x -.5)^2

 ±2.5 +.5 = x = {-2, 3} . . . . . identifies the third solution set for system C

__

remaining problems are done in a similar way.

_____

* DNE = does not exist. There is no matching solution set for the complex numbers that are the solutions to this.

---------------------

<em>Hope this helps!</em>

<em />

<u>Brainliest would be great!</u>

<u />

---------------------

<em><u>With all care,</u></em>

<em><u>07x12!</u></em>

4 0
3 years ago
The weight of a person on or above the surface of the earth varies inversely as the square of the distance the person is from th
AleksandrR [38]
If you do this with a complex set of fractions and let
K = G Me m_space be the same in both parts, there should be some cancellation.

W_earth = 180 lbs

W_earth = K /3900 miles^2
W_space =K  /(3900 + 850)^2

180 / W_space = k/3900^2
x = k / (4750)^2

\frac{180}{Wspace} =  \frac{ \frac{k}{3900^{2} } }{ \frac{k}{4750^{2}} /[tex]\\Now you need to invert and multiply the bottom fraction on the left.\\[tex] \frac{180}{x} {=} \frac{k}{3900^{2}} {*} \frac{4750^{2}}{k} 

The ks cancel out.

You are left with 180/x = 4750^2 / 3900^2 Now cross multiply
180 * 3900^2 = 4750^2  = x
180 * 3900^2 / 4750^2 = x 
180 * 0.67413 = x
x = 121 pounds. Weight is a force, but because all the units on one side are equivalent to the units on the other, the conversions become part of k. Normally you would have to do the conversions, but not in this particular case.

4 0
3 years ago
Read 2 more answers
What inverse operation should be used to isolate the variable in the equation j ÷ 12 = 50?
DerKrebs [107]

Answer:

600

Step-by-step explanation:

50x12=600 you can check this by doing 600/12=50

7 0
3 years ago
Read 2 more answers
PLEASE HELP...AGAIN this is due tomorrow and it's late at noon..
dimaraw [331]
What do you need help with and what subject
4 0
3 years ago
Which option summarizes what gave Chandra Gupta I power
mars1129 [50]

Answer:

Chandra Gupta I, King of India reigned from 320 to about 330 CE and founder of the Gupta empire. He was the grandson of Sri Gupta, the first known leader of the Gupta line. Chandra Gupta I, whose first life is unknown, became the local chief of the kingdom of Magadha parts of the modern state of Bihar.

Step-by-step explanation:

6 0
3 years ago
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