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andreev551 [17]
3 years ago
13

Evaluate. Use p = 3, x = 4 px^2 help pls i am giving brainliest

Mathematics
2 answers:
luda_lava [24]3 years ago
8 0

Answer:

144

Step-by-step explanation:

Aleks04 [339]3 years ago
7 0

Answer:48

Step-by-step explanation:(3)(4)^2=48

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I think it is B but im honestly unsure.

7 0
3 years ago
Please help, I don't know how to do this and need it done quickly, thanks for your help and time! have a good day :)
Olenka [21]
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7 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
-(1/x+3) +4
nlexa [21]

9514 1404 393

Answer:

  • left 3 units
  • up 4 units
  • shape: lower left image

Step-by-step explanation:

For a parent function f(x), the transformations ...

  g(x) = a×f(x -h) +k

cause ...

  • vertical expansion by 'a', reflection over x-axis if negative
  • right shift by 'h'
  • up shift by 'k'

Here, we have parent function f(x) = 1/x with a=-1, h=-3, k=4. Then the transformations are ...

  horizontal shift left 3 units

  vertical shift up 4 units

  reflection over x-axis, so curves are above-left and below-right of the reference point (Note that the reflection is done <em>before</em> the translation.)

4 0
3 years ago
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