The figure A has an area of 40 squared feet.
Why?
In order to know which of the combined rectangles has an area of 40 feet squared, we need to calculate the areas each one of the figures.
So, calculating we have:
<h3>
Figure A:</h3>
Two medium and equals rectangles and one big rectangle.

The figure A is the correct optiopn.
<h3>Figure B:</h3>
Two medium and equals rectangles and one small rectangle.

The figure B is discarded, it's area is less than 40 squared feet.
Figure C:
One medium rectangle and one big rectangle.

The figure C is discarded, it's area is larger than 40 squared feet.
Figure D:
One medium rectangle and one big rectangle:

The figure D is discarded, it's area is larger than 40 squared feet.
Hence, we have that the Figure A is the correct option.
Have a nice day!

Solution:
Given expression is
.
To solve the given expression:
Let us first convert the mixed fraction into improper fraction.
⇒ 
⇒ 
⇒ 
Do cross multiply on both sides of the equation.
⇒ 
⇒ 
⇒ 
Both minus in the numerator and denominator are cancelled.
⇒ 
Hence,
.
The answer would be x = 1