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Contact [7]
3 years ago
11

EXPONENTIAL FUNCTION

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0
Divide by negative = 1/x^|exponent|
1) 1/2^3 = 0.125
2) 1/5^3 = 0.008
3. 1/6^6 = 2.143
4. 1/(5/2)^2 = 0.16
5. 1/(7/3)^3 = 0.079
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187 students in 7th or 8th grade

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4 0
3 years ago
Andrew, who operates a laundry business, incurred the following expenses during the year. ∙ Parking ticket of $250 for one of hi
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Answer:

Option d: $0

Step-by-step explanation:

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7 0
3 years ago
X ^ 2 − 17x − 60
Yakvenalex [24]

{x}^{2}  - 17x - 60 \\ (x + 3)(x - 20)

First we put parentheses and in each bracket we put (X) and then we put the signs x² is positive and the 17X before it is a negative q is positive with negative —> negative, and negative before 17X and negative before the 60 —> positive. And then the number that does not have (x) where did it come from, for example 60 came from 20 x 3 or 30 x 2...etc. We can verify this by multiplying the parentheses together and the same number comes out .

Or it can be checked by multiplying the first bracket 3 with x from the second parenthesis comes out 3X and negative 20 from the second parenthesis with X from the first parenthesis and subtract 3X from –20xcomes out –17X .

I hope I helped you^_^

3 0
3 years ago
What is the maximum number of relative extrema a polynomial function can have?
creativ13 [48]
Relative extrema occur where the derivative is zero (at least for your polynomial function). So taking the derivative we get

<span>20<span>x3</span>−3<span>x2</span>+6=0

</span><span> This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.</span>
4 0
3 years ago
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