All categories

3 years ago

What is equivalent to 5(x + 12) A x +12 B 2x - 60 C 5x + 60 D 2x - 60

Mathematics

1 answer:

Alex73 [517]3 years ago

4 0

Answer:

$\boxed{\boxed{\pink{\sf Option \ C \ is \ correct .}}}$

Step-by-step explanation:

Given to us is , 5 ( x + 12 ) and we need to find which is its equivalent in the given options .

So,

$\bf = 5 ( x + 12 ) \\\\=\bf 5x + 5\times 12 \\\\=\boxed{\red{\bf 5x + 60 }}$

<h3>Hence option C is correct.</h3>

You might be interested in

A plane intersects both bases of a cylinder, passing through the center of each baseof the cylinder. What geometric figure will

myrzilka [38]

When a plane intersects both bases of a cylinder, passing through the center of each base of the cylinder, the cross section formed is a rectangle.

4 0

1 year ago

Teddy is looking for buttons for his snowmen he needs five buttons for each of his snowmen if he has 15 Snowmen and 70 buttons w

Klio2033 [76]

Answer:No, he doesn't have enough buttons. He needs 5 more.

Step-by-step explanation: Do 15×5. Each of the 15 snowmen need 5 each, which equals 75 buttons. Since he has 70 buttons to start off with, he only needs five more buttons.

4 0

3 years ago

F(x, y, z) = z tan−1(y2)i + z3 ln(x2 + 3)j + zk. find the flux of f across s, the part of the paraboloid x2 + y2 + z = 18 that l

Cerrena [4.2K]

$\mathbf F(x,y,z)=z\tan^{-1}(y^2)\,\mathbf i+z^3\ln(x^2+3)\,\mathbf j+z\,\mathbf k$
$\implies\mathrm{div}\mathbf F(x,y,z)=0+0+1=1$

By the divergence theorem, the flux of $\mathbf F$ across the *closed* surface $\mathcal S$ combined with the plane $z=2$ is given by a volume integral over the closed region:

$\displaystyle\iint_{\mathcal S}\mathbf F\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf F\,\mathrm dV$

So in fact, to find the flux over $\mathcal S$ alone, we'll need to subtract the flux of $\mathbf F$ over the planar portion, oriented outward. First, compute the volume integral by converting to cylindrical coordinates:

$x^2+y^2+z=18$
$z=2\implies x^2+y^2=16\implies r^2=16\implies r=4$

$\displaystyle\iiint_{\mathcal R}\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}\int_{z=2}^{z=18-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=128\pi$

If the surface does actually contain $z=2$ , then you can stop here; otherwise, continue.

Now, parameterize the part of the *closed* surface in $z=2$ by

$\mathbf s(r,\theta)=r\cos\theta\,\mathbf i+r\sin\theta\,\mathbf j+2\,\mathbf k$

where $0\le r\le4$ and $0\le\theta\le2\pi$ . We get a surface element

$\mathrm d\mathbf S=(\mathbf s_r\times\mathbf s_\theta)\,\mathrm dr\,\mathrm d\theta=(r\,\mathbf k)\,\mathrm dr\,\mathrm d\theta$

We don't need to worry about the first two components of

and so the surface integral over this region is

$\displaystyle\iint_{z=2\,\land\,x^2+y^2\le16}\mathbf F\cdot\mathrm d\mathbf S=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=4}2r\,\mathrm dr\,\mathrm d\theta=32\pi$

Then the total flux over $\mathcal S$ alone is $(128-32)\pi=96\pi$ .

4 0

3 years ago

Sammy made 150 over 7 days.how much did he make per day

olchik [2.2K]

This calculation will give you Sammy's daily spending rate:

$150

---------- = $21.43/day (to the nearest cent)

7 days

6 0

4 years ago

Please help me answer this :) Explain your answer Will give brainiest

mr Goodwill [35]

A is the answer of this question

6 0

3 years ago