Answer:
The rocket's maximum height will be 1424 feet.
It will reach that height in 4 seconds.
It will reach the ground in 8 seconds.
Step-by-step explanation:
One easy way to find the peak is to find the derivative and solve for zero:
h(t) = -16t² + 128t + 1680
To find the derivative of each term in that format, you simply multiply the coefficient by the exponent, and reduce the exponent by one. In the case of terms with no variable, they disappear. That gives us:
h'(t) = -32t + 128
This derivative describes the rate of change of h with respect to t, so to find the peak, we simply need to solve it for zero:
0 = -32t + 128
32t = 128
t = 4
So the maximum height occurs when t = 4. Let's plug it in to the original equation:
h(t) = -16t² + 128t + 1680
h(4) = -256 + 512 + 1680
h(4) = 1424
So the rocket's maxiumum height is 1424 feet.
And we've already answered the second question, it happens at 4 seconds.
Also, the amount of time going up will be the same as the amount of time going down, which means that it will reach the ground in twice that time, or 8 seconds.
Answer: Hi!
To find the volume of a box (or cube), you multiply length times width times height.
In this case, you have all of the measurements, so all we have to do is multiply them together!
5cm * 8cm * 10cm = 400
So, the volume of this box is 400cm^3!
Hope this helps!
7.53x10^-10 (move the decimal 10 places to the left.
7.53x10^-10= 0.000000000753
Note: Let us consider, we need to find the gradient of line L.
Given:
The given equation of a line is:
The line L passes through the points with coordinates (- 3, 1) and (2, - 2).
To find:
The gradient of the given line and the gradient of line L.
Solution:
Slope intercept form of a line is:
...(i)
We have,
...(ii)
On comparing (i) and (ii), we get
Therefore, the gradient of the given line is -4.
The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:
Therefore, the gradient of the line L is 
.
Answer:
BEFmZ Is the answer i think
Step-by-step explanation:
