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erastovalidia [21]
3 years ago
8

SOMEONE HELP ME HURRY ASAP PLEASE ILL CASHAPP PLEASE HELP

Mathematics
2 answers:
dlinn [17]3 years ago
7 0

Answer:

B

Step-by-step explanation:

76 * 2 = 152

p = 152

152 + 76 + 38 + 94 = 360

Colt1911 [192]3 years ago
6 0

Answer:

48 il take brainliest instead lol

Step-by-step explanation:

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Special Triangles
Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = \frac{\sqrt{3} }{2} and tan30° = \frac{1}{\sqrt{3} } , then

cos30° = \frac{adjacent}{hypotenuse} = \frac{6}{m} = \frac{\sqrt{3} }{2} ( cross- multiply )

\sqrt{3} × m = 12 ( divide both sides by \sqrt{3} )

m = \frac{12}{\sqrt{3} } ← rationalise by multiplying numerator/ denominator by \sqrt{3} )

m = \frac{12}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{12\sqrt{3} }{3} = 4\sqrt{3}

-------------------------------------------------------------------------------

tan30° = \frac{opposite}{adjacent} = \frac{n}{6} = \frac{1}{\sqrt{3} } ( cross- multiply )

\sqrt{3} × n = 6 ( divide both sides by \sqrt{3} )

n = \frac{6}{\sqrt{3} } ← rationalise the denominator

n = \frac{6}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } = \frac{6\sqrt{3} }{3} = 2\sqrt{3}

-----------------------------------------------------------------------------------

7 0
3 years ago
Jamie King wants to buy a new car in 5 years. Jamie
Alenkasestr [34]

Jamie King will have $12,100.25

6 0
3 years ago
Can someone explain to me what 7.1 x 10^-3 is in standard form?
tiny-mole [99]

71000 is in the standard form of 7.1 x 10^-3 .

Step-by-step explanation:

I wish if I could explain you with steps but this is the question I've never done with steps. I always give direct answers from those questions !!

3 0
3 years ago
80% of what number is 190
Degger [83]
80% of 190 = 152
THE ANSWER IS 152
6 0
2 years ago
Read 2 more answers
PLS HLP LOTS OF POINTS
cupoosta [38]
380

3 hundreds  8 tens
2 hundreds 18 tens
1 hundred   28 tens
0 hundred   38 tens
5 0
3 years ago
Read 2 more answers
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