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V125BC [204]
2 years ago
14

I am so confused i need help

Mathematics
2 answers:
Marrrta [24]2 years ago
5 0

Answer:

40

Step-by-step explanation:

There is enough information, so D is not an answer.

10 is far to low. The number is roughly 40. So A is not the answer.

16/20 = .80 that recommended the tooth paste. If you stopped there, 40 would be your answer.  But they took one more survey.

24/30 = .80

So both groups come back with an amount that = 0.8

That means that you should pick 40 as your answer.

Delicious77 [7]2 years ago
3 0
I believe The answer is B 40
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1. What is the measure in radians for the central angle of a circle whose radius is 6 cm and intercept arc length is 5.4 cm?
fgiga [73]
Hello!

1.
find circumferece
c=2pir
c=2*6*pi=12pi
intercept is 5.4

2pi radians=all

part/whole=part/whole
5.4/12pi=x/2pi
times both sides by 12pi
5.4=6x
divide both sides by 6
0.9=x
answer is 0.9 radians



2. 
assuming 9pi/5 radians

find circumference
c=2pir
c=2*26.9*pi
c=53.8pi

arc/circumference=(9pi/5)/2pi

x/(53.8pi)=(9pi/5)/(2pi)
x/(53.8pi)=18/5
times both sides by 53.8pi
x=608.46266 m
about x=608.46 m


Hope this Helps! Have A Wonderful Day! :) 
5 0
3 years ago
Jeremiah can run 5 miles in 37 minutes. At that rate, how long does it take him to run 1 mile?
VashaNatasha [74]
So what you would do is divide 37 minutes by 5 to get 7.4 minutes

answer: 7.4 minutes
3 0
2 years ago
Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
What is the 6th term of the geometric sequence 4, −20, 100, ...?
shtirl [24]
Let's calculate r of this G.P: (-20)/(4) = - 5(100)/(-20) = - 5So r = -5
The formula to find the nth term of a GP is;
a(n) = a(r)ⁿ⁻¹
<u />a₆ = a(r)⁶⁻¹
a₆ = 4(-5)⁵ = -12500<u />
3 0
3 years ago
Read 2 more answers
Find two numbers such that one exceeds the other by 11 and their sum is 73.
Whitepunk [10]

Answer: 31 & 42

<u>Step-by-step explanation:</u>

1st #: x

2nd #: x + 11

1st# + 2nd# = sum

 x    +  x + 11 =  73

         2x + 11 = 73

         2x        = 62

           x          = 31


2nd #: x + 11   = 31 + 11   = 42

5 0
3 years ago
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