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Zepler [3.9K]
3 years ago
15

Plzzz guys, help me with this​

Mathematics
2 answers:
AnnyKZ [126]3 years ago
7 0

Assosiative property will be used here;

= [-3/4] × 5/4 - 6/7 × [-3/4]

= [-3/4 × 5/4] - [6/7 × -3/4]

= -15/16 - [-18/28]

= -15/16 + 18/28

  • On taking l.c.m of 16 & 28 we will get 113, manipulate these two acc. to it.

=( -105+72)/112

= -33/112

babunello [35]3 years ago
4 0

Answer:

Distributive property

Step-by-step explanation:

-3/4*5/4-(-6/7)*(-3/4)

-15/16-(18/28)

-15*7-18*4/112

-105-72/112

-177/112

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

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3 years ago
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