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asambeis [7]
3 years ago
10

972,324,108,36... r= next three terms =

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

Answer:

18,9,4.5

Step-by-step explanation:

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To solve the equation 7 = 3x-2 for x, what operations
Aleks [24]

X=3

Algebra is not one of my fav subjects in math but I do know this!

when solving what you do to one side you do to the other so

if 3x-2=7

the 2 is negative so you change that -2 into a positive

so add 2 to both sides

7+2=9

3x=9

now divide both sides by 3

X= 9/3 (nine over three)

now divide 9 by 3

9÷3=3

x=3

(Hope this helps!)

6 0
3 years ago
Between which two numbers is Negative two-thirds located on a number line?
klemol [59]

Answer:-1 and 0

Step-by-step explanation:

5 0
4 years ago
ben is making bread that calls for 5 cups of flour. His measuring cup only holds 1/2 cup. How many times will ben need to fill t
sladkih [1.3K]

Answer:

10!

Step-by-step explanation:

You will need to put 2 half cups to make 1.

So, 10 half cups is equal to 5 cups.

7 0
3 years ago
Read 2 more answers
Given the polynomial 21x^4+3y-6x^2+34 1. What polynomial must be subtracted from it to obtain 29x^2-7? 2. What polynomial must b
zysi [14]

Answer:

21x^4+3y-35x^2+41 must be subtracted

As you can see, we added -x+2 to this polynomial to obtain a first degree polynomial. (Though really anything with an x would do. For example, 3x, 2221x, or -224x would all work)

Step-by-step explanation:

We have the following polynomial

21x^4+3y-6x^2+34

And need to find a polynomial to subtract from it to get

29x^2-7

This means that if we subtract these two polynomials, we will get our desired polynomial

21x^4+3y-6x^2+34-(29x^2-7)\\\\21x^4+3y-6x^2+34-29x^2+7\\\\21x^4+3y-35x^2+41

Just to be sure, we can then check our work by finding the difference of the first polynomial and the one that we just found

21x^4+3y-6x^2+34-(21x^4+3y-35x^2+41)\\\\21x^4+3y-6x^2+34-21x^4-3y+35x^2-41\\\\-6x^2+34+35x^2-41\\\\29x^2-7

As we got the desired result, we know that this answer is correct.

And now for the second part of the problem. What polynomial must be added to it to obtain a first degree polynomial?

Recall that a first degree polynomial is one that has the total sum of 1. For example the polynomial x+5 is a first degree polynomial, but x+y+5 has a degree of 2.

This means that our desired polynomial needs to only have some amount of x's and constants.

We can do the same thing as the first time and simply subtract our desired result from the first polynomial. For simplicity, let us use the simple polynomial x+2

21x^4+3y-6x^2+34-(x-2)\\\\21x^4+3y-6x^2+34-x+2\\\\21x^4+3y-6x^2-x+36

As you can see, we added -x+2 to this polynomial to obtain a first degree polynomial. (Though really anything with an x would do. For example, 3x, 2221x, or -224x would all work)

7 0
3 years ago
If -2 and 3 are zeroes of quadratic polynomial xsquare + (a+1)x+b then find the value of and b
ohaa [14]

Answer:

a = - 2, b = - 6

Step-by-step explanation:

Substitute the values of the zeros into the polynomial and equate to zero.

x² +(a + 1)x + b

x = - 2 → (- 2)² - 2(a + 1) + b = 0 , that is

4 - 2a - 2 + b = 0

2 - 2a + b = 0 ( subtract 2 from both sides )

- 2a + b = - 2 → (1)

x = 3 → 3² + 3(a + 1) + b = 0, that is

9 + 3a + 3 + b = 0

12 + 3a + b = 0 ( subtract 12 from both sides )

3a + b = - 12 → (2)

Subtract (1) from (2) term by term to eliminate b

5a = - 10 ( divide both sides by 5 )

a = - 2

Substitute a = - 2 into either of the 2 equations and evaluate for b

Substituting into (2)

3(- 2) + b = - 12

- 6 + b = - 12 ( add 6 to both sides )

b = - 6

Thus a = - 2 and b = - 6

4 0
4 years ago
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