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3 years ago

Https://mee t.go ogle.co m/o yi- ta km- tes

Mathematics

1 answer:

coldgirl [10]3 years ago

8 0

That link looks messed up

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What is the area of a rectangle that is 1 1 4 1 4 1 1, start fraction, 1, divided by, 4, end fraction meters long and 3 4 4 3

hjlf

Answer:

4 11/16 m²

Step-by-step explanation:

The formula for the area of a rectangle = Length × Width

From the question:

Length = 1 1/4 m

Width = 3 3/4m

Area of the rectangle =

1 1/4 m × 3 3/4 m

= 5/4 m × 15/4 m

= 75/16 m²

= 4 11/16 m²

Area of the rectangle = 4 11/16 m²

7 0

3 years ago

-2[4-(3b+2)]=5-2(3b+6)

netineya [11]

B= -1/4

Hope this helps

8 0

3 years ago

What is the equation of the line

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

ive helped middle schoolers with this

5 0

3 years ago

Please show your work and explain it.

Maru [420]

Answer:

$f(x)=\dfrac{x+2}{2(x-2)}$

Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$

Next we factor what we can so we can further simplify the rest of the equation:

$=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\$

We can now cancel out (x+2)

$=\dfrac{(x+2)(3x-12)}{(x^2-6x+8)(6)}$

Next we factor out even more:

$=\dfrac{(x+2)(3)(x-4)}{(x-2)(x-4)(6)}$

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

$=\dfrac{(x+2)(1)}{(x-2)(2)}$

And we can now simplify it to:

$=\dfrac{x+2}{2(x-2)}$

6 0

4 years ago

Does anyone know this ???

romanna [79]

Answer:

m<PKN = 270 - m<JKN

Step-by-step explanation:

The measures of the three right angles JKM, MKL, and LKN add to 270 deg.

The measures of the angles JKP and PKN add to 270 deg.

m<PKN = 270 - m<JKN

5 0

3 years ago