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2 years ago

Need help in math anyone please help

Mathematics

2 answers:

Marizza181 [45]2 years ago

8 0

Answer:

what's the question?

Step-by-step explanation:

patriot [66]2 years ago

3 0

How can i help you ? what subject do you need help in ?

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The expression 50 can be simplified to

puteri [66]

Answer:

Step-by-step explanation:

The first step in simplifying the expression of the square root of 50 involves finding factors of 50. This just means we are trying to find two whole numbers that, when multiplied, equal 50. Since 50 is an even number, 2 is going to be a factor, and so we can rewrite 50 as 2 times 25.

6 0

2 years ago

F(x) = 9x^2+30x+25 pls help

lapo4ka [179]

Answer: f(x) =(3x+5)^2

x= -5/3

Step-by-step explanation:

5 0

2 years ago

Simplify (6x2 − 3 − 5x3) − (4x3 + 2x2 − 8).

mezya [45]

(6•2 - 3 - 5•3) - (4•3 + 2•2 - 8)
(12 - 3 - 15) - (12 + 4 - 8)
(9 - 15) - (16 - 8)
(-6) - (8)
-14

7 0

3 years ago

Read 2 more answers

The table below shows the numbers of tickets sold at a movie theater on Friday.

sleet_krkn [62]

Answer:

Number of Adult's tickets sold on Saturday = 3,356

Number of Children's tickets sold on Saturday = 2, 928

Total number of tickets sold over these two days is 8,938.

Step-by-step explanation:

Here, the number of tickets sold on FRIDAY:

Adult Ticket sold = 1,678

Children's Tickets sold = 976

So, the total number of tickets sold on Friday

= Sum of ( Adult + Children's ) tickets = 1,678 + 976 = 2,654 .... (1)

The number of tickets sold on SATURDAY:

Adult Ticket sold = 2 times as many as the number of adult tickets sold

on Friday

= 1,678 x 2 = 3,356

Children's Tickets sold = 3 times as many as the number of children's

tickets sold on Friday.

= 976 x 3 = 2, 928

So, the total number of tickets sold on Saturday

= Sum of ( Adult + Children's ) tickets = 3,356 + 2,928 = 6, 284 .... (2)

Now, the total number of tickets booked in these two days :

Sum of tickets booked on (Friday + Saturday)

= 2,654 + 6, 284 = 8,938

Hence, total number of tickets sold over these two days is 8,938.

7 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago