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3 years ago

Solve k = 1/ 2 mv2 for m

Mathematics

1 answer:

WINSTONCH [101]3 years ago

6 0

k = 1/ 2 mv^2 for m

multiply by 2

2k = m v^2

divide by v^2

(2k)/v^2 =m

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Bradley Is driving to college to move into the dorms for his freshman year.The university he is attending is 107 miles away from

ohaa [14]

Answer:

He has 42 more minutes to drive and 44 miles to cover to arrive at the university

Step-by-step explanation:

If he drives 63 miles in 1 hr

he would drive 107 miles in

107/ 63 = 1.7 hours

to convert 0.7 to time, multiply by 60 = 42 minutes

his total travel time is 1 hr 42 minutes

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3 years ago

Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given freque

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Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

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If we order the data we got the following result. We assume that the midpoint is given by:

$Midpoint= \frac{L.Limit +U.Limit}{2}$

The $Class.Width = U.Limit-L.Limit$

And the limits are given by the lower and upper limit.

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Read 2 more answers

Find the number of terms, n, of the arithmetic series given a1=11, an=95, and Sn=689.

borishaifa [10]

Answer:

Step-by-step explanation:

Its calculate the common difference first.

(95-11)/(n-1).

We also have the sum of these n terms is 689.

So we have the following:

+(11+(95-11)/(n-1))

+(11+2(95-11)/(n-1))

+...

+(11+(n-1)(95-11)/(n-1))

This can be re-expressed alittle:

There are (n) amount of 11's in the addition... also 1+2+3+...+(n-1)=(n-1)(n)/2.

So we have the sum is

11(n)+n(n-1)/2×(95-11)/(n-1)

But this equal to 689.

We need to solve the following equation:

11(n)+n(n-1)/2×(95-11)/(n-1)=689

The (n-1)'s in second term can cancel.

11(n)+n/2×84=689

11n+42n=689

53n=689

n=689/53

n=13

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