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3 years ago

Solve k = 1/ 2 mv2 for m

Mathematics

1 answer:

WINSTONCH [101]3 years ago

6 0

k = 1/ 2 mv^2 for m

multiply by 2

2k = m v^2

divide by v^2

(2k)/v^2 =m

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Please solve step by step.....

natima [27]

The picture is not clear... the Question has got cut at the sides .... please take the picture properly and the post the Question again... please

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No they are not unequal... i. e. the two wires A and B are equal .

$\frac{1}{3}$ of A = $\frac{1}{3}$ of B

=> $\frac{3}{3}$ × A = B

=> 1 × A = B

=> A = B

:. The length of A = the length of B .

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HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

5 0

3 years ago

Ryan and Sarah collect baseball cards. Ryan has 150 baseball cards and collects 10 cards per week. Sarah has 233 baseball cards

ICE Princess25 [194]

Answer:

About 17 weeks

Step-by-step explanation:

Given

Ryan:

$Initial = 150$

$Additional = 10$ (weekly)

Sarah:

$Initial = 233$

$Additional = 5$ (weekly)

Required

Determine the number of weeks they have the same cards

Represent the number of weeks with w:

For Both individuals, number of card at any given week is:

$Initial + Additional * w$

So,

For Ryan, the expression is:

$150 + 10 * w$

$150 + 10w$

For Sarah, the expression is:

$233 + 5 * w$

$233 + 5 w$

To determine the number of weeks, we have to equate both equations:

$150 + 10w= 233 + 5 w$

Collect Like Terms

$10w - 5w = 233 - 150$

$5w = 83$

Solve for w

$w = 83/5$

$w = 16.6$

16.6 implies about 17 weeks, because 16.6 approximates to 17

Conclusively, Ryan and Sarah will have the same number of balls in about 17 weeks

5 0

3 years ago

A. Why does the provided equation support the fact that there is a horizontal asymptote of F(x) that is not

aniked [119]

Applying limits, it is found that since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

The function is given by:

$F(x) = \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

The horizontal asymptote is the limit of the function as x goes to infinity, hence:

$y = \lim_{x \rigtharrow \infty} F(x) = \lim_{x \rigtharrow \infty} \frac{(ax - 3)(x - 2)}{2(x + 3)(x - 2)}$

Considering only the terms with the highest exponents:

$y = \lim_{x \rigtharrow \infty} \frac{ax^2}{2x^2} = \frac{a}{2}$

Since $a \neq 0, \frac{a}{2} \neq 0$ , and hence the horizontal asymptote is not y = 0, thus not being on the x-axis.

For more on horizontal asymptotes and limits, you can check brainly.com/question/11598999

3 0

3 years ago

Please help me out, please ill mark you as brainliest if you get this correct.

dmitriy555 [2]

1. width= 23.8ft
height= 27.3ft
area= 650 sq ft
2. width= 25.8ft
height= 26.4 ft
area= 681 sq ft

3 0

3 years ago

What expressions are equivalent to 20

Diano4ka-milaya [45]

Answer:

What expressions are equivalent to 20

Step-by-step explanation:

since you didn't .show a link this is my guess, i guess.

4x5=20

6 0

4 years ago