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3 years ago

Solve the inequality 4x + 3 < 6 + 2x

Mathematics

2 answers:

Alona [7]3 years ago

6 0

Answer:

x < 3/2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

Mrac [35]3 years ago

5 0

Answer:

the answer is: x< 3 /2

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Answer:

x^3-4x^2+25x-100

Step-by-step explanation:

We have 2 roots -5i and 4. Using the conjugate root theorem for the root -5i, we know that 5i should be another root

Combining the roots into a polynomial gives us:

(x+5i)(x-5i)(x-4)

Expand:

(x^2 + 25)(x-4)

x^3-4x^2+25x-100

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3 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

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3 years ago

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2 years ago

Solve for the value of y in the following system of equations by using the elimination method.

pantera1 [17]

Answer:

I got x=5/2; y=0 lmk if it works

Step-by-step explanation:

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2 years ago

Read 2 more answers

Solve the inequality 4x + 3 < 6 + 2x​

Solve the inequality 4x + 3 < 6 + 2x