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olga2289 [7]
3 years ago
14

Which of the following is a regular quadrilateral

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0

Answer:

(B) square

Step-by-step explanation:

Square (regular quadrilateral): all four sides are of equal length (equilateral), and all four angles are right angles.

oksano4ka [1.4K]3 years ago
6 0

Answer:

B) square is your answer.

Step-by-step explanation:

hope it's help you with write answers.

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Which word expression matches the numerical expression 2 1/4 + 8/3
Brilliant_brown [7]

Answer:

I think the right answer is A

sorry if I am wrong

8 0
3 years ago
Find y and x intercept
Svetlanka [38]
-2x + 3y = 12
x intercept y = 0
-2x = 12
   x = -6

y intercept x = 0
3y = 12
  y = 4

answer
y intercept (0,4)
x intercept (-6,0)

3 0
3 years ago
I WILL GIVE BRAINLIEST
Bumek [7]

Hey there!

ASSUMING!

-3/7m = 12


IF SO!

DIVIDE -7/3 to BOTH SIDES

-7/3 * -3/7m = 12 * 7/3


CANCEL out: -7/3 * (-3/7) because it give you 1

KEEP: 12 * (-7/3) because it give you the m-value


NEW EQUATION: m = 12 * (-7/3)

SIMPLIFY IT!

m = -28


Therefore, your answer is: m = -28

(Option A)


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
3 years ago
Which reason justifies step 2 in the proof
tigry1 [53]
<h3>Answer: C. If two lines are parallel, then the alternate interior angles formed are congruent.</h3>

This is through the alternate interior angles theorem. Angles Q and T pair up as one alternate interior set of angles that are the same measure. The same thing applies to angles X and R.

The identical arrow markers on segments XQ and TR show that those segments are parallel. Segment TQ is one transversal cut (forming alternate interior angles Q and T). Segment XR is the other transversal cut (forming alternate interior angles X and R).

We could say "angle XRT" or "angle TRX" instead of "angle R", though its ideal to use shortcuts whenever possible. The same applies for the other angles as well.

6 0
4 years ago
What is the approximate surface area of a cylinder that's base has a radius of 2, and it's lateral rectangle has a length of 6.2
Kisachek [45]

Answer:

Surface area of cylinder = 50.26 unit² (Approx.)

Step-by-step explanation:

Given:

Radius of base r = 2 units

Width of lateral rectangle = 4 units

Length of lateral rectangle = 6.28 units

Find:

Surface area of cylinder

Computation:

Surface area of cylinder = 2[Area of base] + Area of lateral rectangle

Surface area of cylinder = 2[πr²] + [l][b]

Surface area of cylinder = 2[(22/7)(2)²] + [6.28][4]

Surface area of cylinder = 2[(22/7)(4)] + 25.12

Surface area of cylinder = 25.14 + 25.12

Surface area of cylinder = 50.26

Surface area of cylinder = 50.26 unit² (Approx.)

7 0
3 years ago
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