See the attached picture for the answers.
Answer:
Use Heron's formula; see below.
Step-by-step explanation:
Use Heron's formula.
Let the sides of the triangle have lengths a, b, and c.


Example:
A triangle has side lengths 3, 4, and 5 units.
Find the area of the triangle.








Answer:
30000
Step-by-step explanation:
take 7 it is above four so it goes up but
you need then one behide it to its a 5 so it goes up
Answer:
Marianne is 15 years old and her brother is 5 years old; is the relationship between their ages proportional?
Step-by-step explanation:
i just did it
The three points A,B,C are all points on this circle.
Each point is then equal distance from the center, that distance being the radius of the circle.
Using the distance formula, we can find the center of the circle (x,y):

Plugging in points A and B into distance formula, then setting them equal to each other gives:

Right away we can cancel out the x terms leaving:

Expand Left side and Solve for y:


Plug in points B and C as before:

Here we can cancel the y-terms.
Expand and solve for x:



Therefore the center of the circle is the point (6,3)