Answer:
About 1 gal
Step-by-step explanation:
When you are estimating with fractions, you should round them off to the closest integers that you can work with in your head.
⅓, ⅕, and ½ are all close to zero, but that's absurd, because Neil clearly has some paint
.
Instead, let's estimate that ⅓ gal + ⅕ gal make about ½ gal.
They still have the other ½ gal, and
½ gal + ½ gal = 1 gal.
Neil has about 1 gal of paint.
93.
EXPLANATION:
Add all the numbers together
- that from 360
93
Answer:
![4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B2%7Dx%28%5Csqrt%5B3%5D%7By%7D%2B3xy%5Csqrt%5B3%5D%7By%7D%20%29)
Step-by-step explanation:
Let's start by breaking down each of the radicals:
![\sqrt[3]{16x^3y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16x%5E3y%7D)
Since we're dealing with a cube root, we'd like to pull as many perfect cubes out of the terms inside the radical as we can. We already have one obvious cube in the form of
, and we can break 16 into the product 8 · 2. Since 8 is a cube root -- 2³, to be specific, we can reduce it down as we simplify the expression. Here our our steps then:
![\sqrt[3]{16x^3y}\\=\sqrt[3]{2\cdot8\cdot x^3\cdot y}\\=\sqrt[3]{2} \sqrt[3]{8} \sqrt[3]{x^3} \sqrt[3]{y} \\=\sqrt[3]{2} \cdot2x\cdot \sqrt[3]{y} \\=2x\sqrt[3]{2}\sqrt[3]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16x%5E3y%7D%5C%5C%3D%5Csqrt%5B3%5D%7B2%5Ccdot8%5Ccdot%20x%5E3%5Ccdot%20y%7D%5C%5C%3D%5Csqrt%5B3%5D%7B2%7D%20%5Csqrt%5B3%5D%7B8%7D%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%5Csqrt%5B3%5D%7By%7D%20%5C%5C%3D%5Csqrt%5B3%5D%7B2%7D%20%5Ccdot2x%5Ccdot%20%5Csqrt%5B3%5D%7By%7D%20%5C%5C%3D2x%5Csqrt%5B3%5D%7B2%7D%5Csqrt%5B3%5D%7By%7D)
We can apply this same technique of "extracting cubes" to the second term:
![\sqrt[3]{54x^6y^5} \\=\sqrt[3]{2\cdot27\cdot (x^2)^3\cdot y^3\cdot y^2} \\=\sqrt[3]{2}\sqrt[3]{27} \sqrt[3]{(x^2)^3} \sqrt[3]{y^3} \sqrt[3]{y^2}\\=\sqrt[3]{2}\cdot 3\cdot x^2\cdot y \cdot \sqrt[3]{y^2} \\=3x^2y\sqrt[3]{2} \sqrt[3]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B54x%5E6y%5E5%7D%20%5C%5C%3D%5Csqrt%5B3%5D%7B2%5Ccdot27%5Ccdot%20%28x%5E2%29%5E3%5Ccdot%20y%5E3%5Ccdot%20y%5E2%7D%20%5C%5C%3D%5Csqrt%5B3%5D%7B2%7D%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7B%28x%5E2%29%5E3%7D%20%5Csqrt%5B3%5D%7By%5E3%7D%20%5Csqrt%5B3%5D%7By%5E2%7D%5C%5C%3D%5Csqrt%5B3%5D%7B2%7D%5Ccdot%203%5Ccdot%20x%5E2%5Ccdot%20y%20%5Ccdot%20%5Csqrt%5B3%5D%7By%5E2%7D%20%5C%5C%3D3x%5E2y%5Csqrt%5B3%5D%7B2%7D%20%5Csqrt%5B3%5D%7By%7D)
Replacing those two expressions in the parentheses leaves us with this monster:
![2(2x\sqrt[3]{2}\sqrt[3]{y})+4(3x^2y\sqrt[3]{2} \sqrt[3]{y})](https://tex.z-dn.net/?f=2%282x%5Csqrt%5B3%5D%7B2%7D%5Csqrt%5B3%5D%7By%7D%29%2B4%283x%5E2y%5Csqrt%5B3%5D%7B2%7D%20%5Csqrt%5B3%5D%7By%7D%29)
What can we do with this? It seems the only sensible thing is to look for terms to factor out, so let's do that. Both terms have the following factors in common:
![4, \sqrt[3]{2} , x](https://tex.z-dn.net/?f=4%2C%20%5Csqrt%5B3%5D%7B2%7D%20%2C%20x)
We can factor those out to give us a final, simplified expression:
![4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7B2%7Dx%28%5Csqrt%5B3%5D%7By%7D%2B3xy%5Csqrt%5B3%5D%7By%7D%20%29)
Not that this is the same sum as we had at the beginning; we've just extracted all of the cube roots that we could in order to rewrite it in a slightly cleaner form.
Add the total of the 3 things bought and subtract from what they gave the cashier:
20.34 + 24.08 + 5.08 = 49.50 total
50 - 49.50 = 0.50
The shopkeeper kept 0.50
Answer:
Step-by-step explanation:
I think you meant x^(3/2). This breaks down in at least two ways:
[x^3]^(1/2), or √(x^3)m or √x³), or
[x^(1/2)]^3 = (√x)^3