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Alex
3 years ago
15

What is the scientific notation if 36000x10^-8? ​

Mathematics
2 answers:
bezimeni [28]3 years ago
8 0

Answer:

the scientific notation of

36000×10^{-8}=36000/100000000=3.6×10^{4}/10^{-8}

=3.6×10^{4-8}=3.6*10^{-4}

sertanlavr [38]3 years ago
6 0

Answer:

3.6 * 10^-4

Step-by-step explanation:

36000x10^-8

The number must be between 1 and 10

36000.

Move the decimal 4 places to the left, so add 4 to the exponent

3.6 * 10^(-8+4)

3.6 * 10^-4

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mariarad [96]

Answer:

About 1 gal  

Step-by-step explanation:

When you are estimating with fractions, you should round them off to the closest integers that you can work with in your head.

⅓, ⅕, and ½ are all close to zero, but that's absurd, because Neil clearly has some paint .

Instead, let's estimate that ⅓ gal + ⅕ gal  make about ½ gal.

They still have the other ½ gal, and  

½ gal + ½ gal = 1 gal.

Neil has about 1 gal of paint.

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3 years ago
Sasha needs to score at least 360 points
IgorC [24]
93.
EXPLANATION:
Add all the numbers together
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3 years ago
What is the following sum?<br>(please show how you worked it out)
AleksAgata [21]

Answer:

4\sqrt[3]{2}x(\sqrt[3]{y}+3xy\sqrt[3]{y} )

Step-by-step explanation:

Let's start by breaking down each of the radicals:

\sqrt[3]{16x^3y}

Since we're dealing with a cube root, we'd like to pull as many perfect cubes out of the terms inside the radical as we can. We already have one obvious cube in the form of x^3, and we can break 16 into the product 8 · 2. Since 8 is a cube root -- 2³, to be specific, we can reduce it down as we simplify the expression. Here our our steps then:

\sqrt[3]{16x^3y}\\=\sqrt[3]{2\cdot8\cdot x^3\cdot y}\\=\sqrt[3]{2} \sqrt[3]{8} \sqrt[3]{x^3} \sqrt[3]{y} \\=\sqrt[3]{2} \cdot2x\cdot \sqrt[3]{y} \\=2x\sqrt[3]{2}\sqrt[3]{y}

We can apply this same technique of "extracting cubes" to the second term:

\sqrt[3]{54x^6y^5} \\=\sqrt[3]{2\cdot27\cdot (x^2)^3\cdot y^3\cdot y^2} \\=\sqrt[3]{2}\sqrt[3]{27} \sqrt[3]{(x^2)^3} \sqrt[3]{y^3} \sqrt[3]{y^2}\\=\sqrt[3]{2}\cdot 3\cdot x^2\cdot y \cdot \sqrt[3]{y^2} \\=3x^2y\sqrt[3]{2} \sqrt[3]{y}

Replacing those two expressions in the parentheses leaves us with this monster:

2(2x\sqrt[3]{2}\sqrt[3]{y})+4(3x^2y\sqrt[3]{2} \sqrt[3]{y})

What can we do with this? It seems the only sensible thing is to look for terms to factor out, so let's do that. Both terms have the following factors in common:

4, \sqrt[3]{2} , x

We can factor those out to give us a final, simplified expression:

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6 0
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bagirrra123 [75]

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7 0
3 years ago
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stiv31 [10]

Answer:

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I think you meant x^(3/2).  This breaks down in at least two ways:

[x^3]^(1/2), or √(x^3)m or √x³), or

[x^(1/2)]^3 = (√x)^3

3 0
3 years ago
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