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Tomtit [17]
3 years ago
6

The cost of renting a boat is $51 for 4 hours. Which of the following is not an equivalent rate? Give the letter of your answer

and justify your answer. Show your work.
A. $76.50 for 6 hours

B. $38.25 for 3 hours

C. $89.25 for 7 hours

D. $63.00 for 5 hours
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

D. $63.00 for 5 hours

Step-by-step explanation:

The actual cost to rent the boat per hour is $12.75 when you multiply all the other hours by 12.75 it equals the correct amount except for (D) 5 ×12.75 = 63.75

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
3 years ago
What are the first four terms if the sequence represented by the expression n (n-1) -4?
shepuryov [24]
We have that
<span>n (n-1) -4

for n=1
a1=1*(1-1)-4------> a1=-4

for n=2
</span>a2=2*(2-1)-4------> a2=-2

for n=3
a3=3*(3-1)-4------> a3=2

for n=4
a4=4*(4-1)-4------> a4=8

the answer is
-4,-2, 2, 8
5 0
3 years ago
Fay has a lemonade stand.
AnnyKZ [126]

Answer:

her total profit is 3

Step-by-step explanation:

1.50 x 30 = 45

to find total profit - 45-42= 3

5 0
3 years ago
Read 2 more answers
Please answer this question I need this urgent Help meeeee
iren [92.7K]

Answer:

\frac{s}{2t}

Step-by-step explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

a^{x} *a^{y} = a^{x + y}

So let's group like terms in the numerator:

4r^{3} r^{-5} s^{-2} s^{-1}t   We can add terms like in the example.

4 r^{-2} s^{-3} t

Let's rearrange the denominator.

8r^{-2} s^{-4} t^{2}

Now we have:

\frac{4r^{-2} s^{-3}t}{8 r^{-2} s^{-4} t^{2} }  Cancel like terms

4/8 = 1/2    

r^{-2} /r^{-2} = 1  So it cancels

s^{-3} / s^{-4} = s^{-1} = s Since s is raised to the -1 it goes on top and becomes s.

t / t^{2}  = 1/t

Now we combine everything back together:

\frac{s}{2t}

8 0
3 years ago
Select the correct answer. What is the opposite of ? A. B. C. D. E.
Helga [31]

Answer: what are the options?

Step-by-step explanation:

7 0
3 years ago
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