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Diano4ka-milaya [45]
3 years ago
15

En tres partidos de besisbol de fin de Semana, hubo 125,429 espectadores .La Semana siguiente hubi 86,353 especradores cuantos e

spectadores en total presenciaron los seis partidos en total
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Answer:

211,782

Step-by-step explanation:

Esta pregunta es muy fácil porque Los espectadores en total que presenciaron los seis partidos en total es la suma de ambos.

125,429 en uno lado y 86,353 en uno lado. Y eso es igual

125,429 + 86,353 = 211,782

Los espectadores en total que presenciaron los seis partidos en total es 211,782

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If x+y=12 and xy=15,find the value of (x^2+y^2)
Mice21 [21]

Answer:  x^2+y^2=\dfrac{105\pm 18\sqrt6}{2}

<u>Step-by-step explanation:</u>

EQ1:  x + y = 12     --> x = 12 - y

EQ2:  xy = 15      

Substitute x = 12-y into EQ2 to solve for y:

(12 - y)y = 15

12y - y² = 15

0 = y² - 12y + 15

    ↓     ↓         ↓

  a=1   b= -12   c=15

.\  y=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\.\quad =\dfrac{-(-12)\pm \sqrt{(-12)^2-4(1)(15)}}{2(1)}\\\\\\.\quad =\dfrac{12\pm \sqrt{144-120}}{2}\\\\\\.\quad =\dfrac{12\pm \sqrt{24}}{2}\\\\\\.\quad =\dfrac{12\pm 2\sqrt{6}}{2}\\\\\\.\quad =6\pm \sqrt{6}

Now, let's solve for x:

xy=15\\\\x(6\pm\sqrt6)=15\\\\x=\dfrac{15}{6\pm\sqrt6}\\\\\\x=\dfrac{15}{6\pm\sqrt6}\bigg(\dfrac{6\pm\sqrt6}{6\pm\sqrt6}\bigg)=\dfrac{6\pm \sqrt6}{2}

Lastly, find x² + y² :

y^2=(6\pm \sqrt6)^2\quad \rightarrow \quad y^2=36\pm 12\sqrt6 +6\quad \rightarrow \quad y^2=42\pm 12\sqrt6

x^2=\bigg(\dfrac{6\pm \sqrt6}{2}\bigg)^2\quad \rightarrow \quad x^2=\dfrac{42\pm 12\sqrt6}{4}\quad \rightarrow \quad x^2=\dfrac{21\pm 6\sqrt6}{2}

                                                                                 

x^2+y^2=\dfrac{21\pm 6\sqrt6}{2}+42\pm 12\sqrt6\\\\\\.\qquad \quad = \dfrac{21\pm 6\sqrt6}{2}+\dfrac{84\pm 24\sqrt6}{2}\\\\\\. \qquad \quad = \dfrac{105\pm 18\sqrt6}{2}

5 0
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alex41 [277]
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Isabel is designing a new fish tank that is shaped like a triangular prism with lateral faces made of glass. The bases of the pr
Bas_tet [7]

Answer:

192in^2

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3 years ago
A device in your school Lab releases gas at a rate of, which means 0.25 of a liter of gas is released every second. The density
Snezhnost [94]

Answer:

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This means 1.075 grams of the gas is released in 1 sec, therefore,

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3 0
3 years ago
Read 2 more answers
Increase 12 1/2 cm by 25 mm
kondor19780726 [428]
12 1/2 = 12.5 2.5mm = 2.5 cm So the answer would be 15 cm
3 0
3 years ago
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