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8090 [49]
3 years ago
14

A device in your school Lab releases gas at a rate of, which means 0.25 of a liter of gas is released every second. The density

of the gas is, which means that there are 4.3 grams of the gas in one liter. Set up the calculation to find the number of seconds it will take for the device to release 154 grams of the gas.
Drag each tile to the correct location. The tiles can be used more than once.
Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0

Answer:

154g x 1 liter/4.3 grams x 1 second/0.25 liters

Step-by-step explanation:

Snezhnost [94]3 years ago
3 0

Answer:

143.26 sec

Step-by-step explanation:

Density = 4.3 g/l

Volume flow rate = 0.25 l/s

Mass flow rate = density x volume flow rate

= 4.3 x 0.25 = 1.075 g/s

This means 1.075 grams of the gas is released in 1 sec, therefore,

Time taken for leakage of 154 g of gas is

t = 154/1.075 = 143.26 sec

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The next step is to determine the number of students who study only each of the courses.

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