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irakobra [83]
3 years ago
9

What is 57 divided by 20

Mathematics
2 answers:
lozanna [386]3 years ago
6 0

Answer:

2.85

Step-by-step explanation:

navik [9.2K]3 years ago
4 0

Answer: 2.85

Step-by-step explanation:

57/20 = 2.85

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3 square root of negative 125
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Lulla Rabbit’s class has 70 pencils and 105 crayons. If both can be evenly divided among the students, what is the maximum numbe
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Need the answer to number 8 pls
Rama09 [41]
We can split it up into

( \frac{x^4+2x^2}{x^2+2})+(  \frac{1}{x^2+2} )= (\frac{x^2(x^2+2)}{x^2+2})+(  \frac{1}{x^2+2} )x^2+\frac{1}{x^2+2}
I see you were supposed to use synthetic division

not sure what the 'related function is'
but as |x| approaches positivie infinity, y approaches positive infinity
as |x| approaches negative infinity, y approaches positive infinity

for the original function
as x approaches positivie infinity x^2+ \frac{1}{x^2+2} approaches positive infinity
as x approaches negative infinity x^2+ \frac{1}{x^2+2} approaches positive infinity
this is due to the x^2 term making it positive
6 0
4 years ago
One positive integer is 3 greater than 4 times another positive integer. If the product of the two integers is 76, then what is
andrew11 [14]

Answer:

The sum of the two integers is 23

Step-by-step explanation:

Let one integer be x and the other integer be y

Then according to the statement "One positive integer is 3 greater than 4 times another positive integer.."

x be the integer that is One positive integer is 3 greater than 4 times another positive integer.

Then

x= 3+4y----------------------------------(1)

Product of the two integer is 76, this can  written as

x \times y =76

substituting the values of x from eq(1)

( 3+4y) \times y =76

3y + 4y^2 = 76

3y + 4y^2-76= 0

4y^2 + 3y -76= 0

Solving the quadratic equation equation we get

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

here

a = 4

b= 3

c = -76

susbtituting the above values in the formula

y=\frac{-3 \pm \sqrt{3^2-4(4)(-76)}}{2(4)}

y=\frac{-3 \pm \sqrt{9- 4(4)(-76)}}{8}

y=\frac{-3 \pm \sqrt{9- (16)(-76)}}{8}

y=\frac{-3 \pm \sqrt{9- (-1216)}}{8}

y=\frac{-3 \pm \sqrt{9 + 1216}}{8}

y=\frac{-3 \pm \sqrt{1225}}{8}

y=\frac{-3 \pm 35}{8}

y=\frac{-3 +35}{8}                       y=\frac{-3 -35}{8}    

y=\frac{32}{8}                             y=\frac{-38}{8}

y= 4                                                           y =  −4.75

Since in the  question it is given that it is a positive integer

so  y = 4

substituting y=4 in eq (1) we get,

x= 3+4(4)

x= 3+16

x= 19

The sum of the two integers

=> x + y

=> 19+4

=>23

8 0
4 years ago
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